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3 years ago

Simplify this expression: -2x + 3 – (5 – 6x). Can someone pls explain how to do this dont just give the awnser

Mathematics

1 answer:

Verizon [17]3 years ago

5 0

Answer:

-2x + 3 – (5 – 6x) = 4x - 2

Step-by-step explanation:

The given expression is :

-2x + 3 – (5 – 6x)

We need to simplify the above expression. First opening the brackets.

-2x + 3 – (5 – 6x) = -2x + 3 – 5 + 6x

Taking like terms together,

= -2x+6x + 3 -5

= 4x - 2

So, the simplified expression is 4x - 2.

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Answer:

Step-by-step explanation:

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3 years ago

Use the graph below to answer the following question:

larisa [96]

ANSWER

B) -1

EXPLANATION

From the graph,

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$= \frac{f(4) - f(1)}{4 - 1}$

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$= \frac{0 - 3}{3}$

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$= \frac{-3}{3} = -1$

The correct choice is .

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3 years ago

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A line has a slope of zero and passes through the point (-2, 3). Which of the following points must also lie on the line?

brilliants [131]

Answer:

(5,3)

Step-by-step explanation

Because the slope is 0, it means its a horizontal line. because the horizontal is on 3, then it doesnt matter what x is as long as y is 3 if that makes any sense.

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3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.