All categories

3 years ago

A line has a slope of zero and passes through the point (-2, 3). Which of the following points must also lie on the line?

Mathematics

1 answer:

brilliants [131]3 years ago

7 0

Answer:

(5,3)

Step-by-step explanation

Because the slope is 0, it means its a horizontal line. because the horizontal is on 3, then it doesnt matter what x is as long as y is 3 if that makes any sense.

You might be interested in

The sum of the digits of a two-digit number is 5. If nine is subtracted from the number, the digits will be reversed. Find the n

Komok [63]

The number is 32
X-9=23

5 0

2 years ago

Helpppppp helpppppppp plssssssssss

Vinil7 [7]

Answer:

Scales-No equal sides

Isosceles- 2 Equal

Equilateral-

Right-90 degree

Obtuse- Obtuse Angle

8 0

3 years ago

What is the answer to (−t/3)^2?

Sloan [31]

Answer:

Simplify the expression.

t^/9

Step-by-step explanation:

7 0

3 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago

7) 2x + y = 7<br> What is the intercept

posledela

Answer:

2x + y = 7

x=7/2

y=7

Step-by-step explanation:

to find y itercept =0

to find x intercept=0

5 0

3 years ago