Answer:
A. 60,000
Step-by-step explanation:
The answer is A because 2 × 3 is 6 then you add the 4 0's. So it would be 60,000
Answer:
2.35 calls
Step-by-step explanation:
The presented scenario can be modeled by a Poisson distribution with an average number of calls (μ) of 5.5 during the noon hour on Mondays.
Therefore, the standard deviation for the number of calls received, X, is given by:
The standard deviation of X is 2.35 calls.
Answer:
#4 is option one 18 miles
Step-by-step explanation:
Step-by-step explanation:
"There are several flights that have very long delays."
True. On the boxplot, we can see several outliers greater than the maximum.
"More than 25% of flights are either exactly on time or arrive early."
False. According to the 5 number summary, 25% of the flights are between -55 and 13. So less than 25% of the flights are on time or early.
"About 50% of flights are delayed between 13 and 35 minutes."
False. According to the 5 number summary, 25% of the flight times are less than 13 minutes, and 50% of the flights are less than 35 minutes. So 25% of the flights are delayed between 13 and 35 minutes, not 50%.
"About 25% of flights are delayed by more than 78 minutes."
True. According to the 5 number summary, 75% of the flights are delayed less than 78 minutes. Which means 25% of the flights are delayed more than 78 minutes.
That is about right... 2,514 X 2 = 5,028 so he is about 1,000 off. I will leave the rest to you.
