Complete question is;
A skull cleaning factory cleans animal skulls and other types of animals using flesh eating Beatles. The factory owner started with only 13 adult beetles.
After 35 days, the beetle population grew to 26 adult beetles. How long did it take before the beetle population was 13,000 beetles?
Answer:
349 days.
Step-by-step explanation:
We are given;
Initial amount of adult beetles; A_o = 13
Amount of adult beetles after 35 days; A_35 = 26
Thus can be solved using the exponential formua;
A_t = A_o × e^(kt)
Where A_t is the amount after time t, t is the time and k is a constant.
Plugging in the relevant values;
26 = 13 × e^(35k)
e^(35k) = 26/13
e^(35k) = 2
35k = In 2
35k = 0.6931
k = 0.6931/35
k = 0.0198
Now,when the beetle population is 12000,we can find the time from;
13000 = 13 × e^(k × 0.0198)
e^(k × 0.0198) = 13000/13
e^(k × 0.0198) = 1000
0.0198k = In 1000
0.0198k = 6.9078
k = 6.9078/0.0198
k ≈ 349 days.
Answer:
Step-by-step explanation:
Given the approximate demand function of night drink expressed as;
p^2+200q^2=177,
p is the price (in dollars) and;
q is the quantity demanded (in thousands).
Given
p = $7
q = 800
Required
dq/dp
Differentiating the function implicitly with respect to p shown;
2p + 400d dq/dp = 0
400q dq/dp = -2p
200qdq/dp = -p
dq/dp = -p/100q
substitute p and q into the resulting equation;
dq/dp = -7/100(800)
dq/dp = -7/80000
dq/dp = -0.0000875
This means that the rate of change of quantity demanded with respect to the price is -0.0000875
Answer:
84
Step-by-step explanation:
30% * $280
= 84
So, the sale price is $84
