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LenaWriter [7]
2 years ago
9

Help please i need the correct answer

Mathematics
1 answer:
aivan3 [116]2 years ago
5 0

Answer:

the first one will be a <u>positive correlation</u>

the answer for the second Q will be 16

Step-by-step explanation:

have a nice day

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Given that sinФ = 8/17 and cos Ф &lt; 0:
Gekata [30.6K]

Answer:

1) The terminal side lies in quadrant 2

2) cosФ = -15/17

3) tanФ = -8/15

Step-by-step explanation:

1) First, we should realize that since sinФ = 8/17, it is positive. Thus, Ф must be in quadrants 1 or 2. And since cosФ is negative, Ф must be in quadrant 2 because cos, sin, and tan are all positive in quadrant 1

2) Next, we must realize that the sides given are a 8-15-17 right triangle. And in this case, since sinФ = 8/17, cosФ should be 15/17. But since cosФ is negative, cosФ = -15/17

3) Lastly, tanФ is opposite/adjacent. Since opposite of Ф is 8 and adjacent of Ф is 15, then tanФ should be 8/15, but since Ф is in quadrant 2, then tanФ is -8/15

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3 years ago
A the bead shop, there are 25 rows of beads. If there are 320 beads in each row, how many beads are in the shop?
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The answer would be 8,000 because one row = 320 beads, and 25x320=8,000
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Jim and Mark left a 20% tip after having lunch at a restaurant. The amount of the tip was $12. Mark's lunch cost $16. Write an e
Vlad1618 [11]

Answer:

$44

Step-by-step explanation:

Use formula

% out of 100/100% = part/whole

20%/100 = 12/16+x

Cross multiply

(12)(100) = (20)(16+x)

1200=320+20x

Solve for x

1200-320 = 20x

880 = 20x

880/20 = x

44 = x

Jim's lunch was $44.

8 0
3 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
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