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Aliun [14]
3 years ago
10

What would be the slope of (1,-2) and (3,0)

Mathematics
2 answers:
vivado [14]3 years ago
6 0

Answer:

1

Step-by-step explanation:

Hello :)

So to answer this problem, we can use the rise over run formula.

The rise is the difference of any two y values.

The run is the difference of the x values from the same two y values.

This question gives us 1,-2 and 3,0

We can use them for the formula:

-2 - 0 divided by 1 - 3

-2/-2 = 1

sweet-ann [11.9K]3 years ago
4 0

Answer:

m=1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (1, -2)

Point (3, 0)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute [Slope Formula]:                    m=\frac{0+2}{3-1}
  2. Evaluate Addition/Subtraction:              m=\frac{2}{2}
  3. Evaluate Division:                                   m=1
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Answer:

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Step-by-step explanation:

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  Tan = Opposite/Adjacent

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Multiplying by 6 gives ...

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2 years ago
A line that includes the points (9,
IceJOKER [234]
Your numbers are all over the place, I will assume that you are saying that the slope is 13.

Looking at the formula for calculating slope/gradient, it is Rise/Run. 
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So by using this formula, you get:
 
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Therefore 1/(v - 9) = 13
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you rearrange it to 13v = 118
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You can check your answer by putting this value back into the gradient formula.
 
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Step-by-step explanation:

29x - 3 + 15x + 7 = 180° because these two angles are supplementary

if we add like terms

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44x = 176 divide both sides by 44

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since we found the value of x let's rewrite the equation

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3 years ago
If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?​
Oduvanchick [21]

\large\underline{\sf{Solution-}}

<u>Given:</u>

\rm \longmapsto x = a \sin \alpha  \cos \beta

\rm \longmapsto y = b \sin \alpha  \sin \beta

\rm \longmapsto z = c\cos \alpha

Therefore:

\rm \longmapsto \dfrac{x}{a}  = \sin \alpha  \cos \beta

\rm \longmapsto \dfrac{y}{b}  = \sin \alpha  \sin \beta

\rm \longmapsto \dfrac{z}{c} = \cos \alpha

Now:

\rm =  \dfrac{ {x}^{2} }{ {a}^{2}} +  \dfrac{ {y}^{2} }{ {b}^{2} } +  \dfrac{ {z}^{2} }{ {c}^{2} }

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