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motikmotik
3 years ago
6

Evaluate this expression when a = 3, b = 4, c = 6 : ab-c

Mathematics
2 answers:
Lana71 [14]3 years ago
7 0
You just going to have to plug it in.
3(4)-6
=6
Harrizon [31]3 years ago
5 0
Answer is 6.

3x4=12, 12-6=6
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Helped needed! 20 points and brainliest of answered right !
svp [43]

Answer:

1. Cluster sampling

2. When finding a fair sample

3. Simple random sampling

5 0
4 years ago
The length of a side and corresponding height of a triangle are (x+3) and (2x-5) given that area of triangle is 20cm^2. Find the
vaieri [72.5K]

Answer:

x = 5

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h is height )

Here A = 20, b = (x + 3) and h = (2x - 5) , then

\frac{1}{2} (x + 3)(2x - 5) = 20 ← multiply both sides by 2

(x + 3)(2x - 5) = 40 ← expand left side using FOIL

2x² + x - 15 = 40 ( subtract 40 from both sides )

2x² + x - 55 = 0 ← in standard form

(x - 5)(2x + 11) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

2x + 11 = 0 ⇒ 2x = - 11 ⇒ x = - 5.5

But x > 0 , so x = 5

8 0
3 years ago
HURRYYY!!
MrMuchimi

Answer:

The middle one

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A ball is launched upward from a height 40 feet above ground level. The ball’s height at t seconds is given by -16t^2=128=40 .
Nesterboy [21]

Answer:

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

Step-by-step explanation:

<u><em>The correct question is</em></u>

A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?

we have

h(t)=-16t^{2}+128t+40

so

For h(t)=100 ft

substitute in the equation and solve for x

-16t^{2}+128t+40=100

-16t^{2}+128t-60=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+128t-60=0

so

a=-16\\b=128\\c=-60

substitute in the formula

x=\frac{-128(+/-)\sqrt{128^{2}-4(-16)(-60)}} {2(-16)}

x=\frac{-128(+/-)\sqrt{12,544}} {-32}

x=\frac{-128(+/-)112} {-32}

x=\frac{-128(+)112} {-32}=0.5

x=\frac{-128(-)112} {-32}=7.5

therefore

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

7 0
4 years ago
True or false? <br><br> this is the equation of a horizontal hyperbola (y-2)^2/16-(x+1)^2/144=1
Mars2501 [29]
<span>its false I hope I helped</span>
4 0
3 years ago
Read 2 more answers
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