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Elina [12.6K]
3 years ago
11

What the percent of 160 is 56? Use the bar model

Mathematics
1 answer:
kow [346]3 years ago
8 0

Answer:

35%

Step-by-step explanation:

See attached for visual

  • 160= 8*20
  • 8 = 1/20 = 5% of 160
  • 56= 8*7
  • 7*5% = 35%

56 is 35% of 160

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-4/5 to the power of 2 times -3/50
Crazy boy [7]
=(-4/5)^2 * -3/50
square -4/5 first; remember -4/5^2 is the same as -4/5 * -4/5

=(-4/5 * -4/5) * -3/50
multiply -4 numerators; multiply 5 denominators

=(-4 * -4)/(5 * 5) * -3/50

=16/25 * -3/50
multiply numerators 16 & -3; multiply denominators 25 & 50

=(16 * -3)/(25 * 50)
= -48/1250

simplify by 2
= -24/625 (or -0.0384)


ANSWER: -24/625 (or -0.0384)

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
I need help with this question... phenobarbital elixir contains 2 grams in 1 liter of elixir. How many milligrams of phenobarbit
posledela

To solve this problem, all we need is the conversion factor.

We know that there are:

1 liter = 202.884 teaspoons

 

Therefore the mass of Phenobarbital is:

mass = (2 grams / 1 Liter) * (1 teaspoon) * (1 Liter / 202.884 teaspoons)

<span>mass = 0.00986 g = 9.86 x 10^-3 g = 9.86 mg</span>

8 0
4 years ago
Read 2 more answers
Hellpppppppopppppppppppppp meeeeeeeeee pleassssse
Ilya [14]
????I don’t get what u need help with
5 0
3 years ago
How to solve this for x
timama [110]

the answer is x= 10.

the steps would go like this.

4 + 3/5 × (15 + 2x) = 25

4 + 9 + 6/5x = 25

13 + 6/5x = 25

65 + 6x = 125

6x = 125 -65

6x = 60

x = 10

hope this helps



5 0
3 years ago
A class consists of 10 male and 10 female students. if four students are selected at random, without replacement, what if four s
Flura [38]
\displaystyle&#10;|\Omega|=\binom{20}{4}=\dfrac{20!}{4!16!}=\dfrac{17\cdot18\cdot19\cdot20}{2\cdot3\cdot4}=4845\\&#10;|A|=\binom{10}{4}=\dfrac{10!}{4!6!}=\dfrac{7\cdot8\cdot9\cdot10}{2\cdot3\cdot4}=210\\\\&#10;P(A)=\dfrac{210}{4845}=\dfrac{14}{323}\approx4.3\%
8 0
3 years ago
Read 2 more answers
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