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Irina-Kira [14]
3 years ago
9

Your job is to choose a data structure to implement polynomials whose coefficients are positive integers, such as 17x^4+4x^3+0x^

2+6x+12x^0
Here are three possible implementations.
I. As a two-dimensional array boolean values: coeff [c] [i] is true if and only if c * x^i is a tem of the polynomial.
II. As a tree map with Integer keys and values. Ifcx is a tem of the polynomial, then we added the following correspondence to the map: coeff.put (new Integer (i), new Integer (c)
III As a hash set of objects of type
public class Termi //based on power public int hashcode (... public Boolean equals (Object obj).. private int coefficient; //based on power private int power
Computers and Technology
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

3

Explanation:

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rocess inputs using the following 1) Write a function that inputs numerical digits in the range of an unsigned short. 2) Write a
yawa3891 [41]

Answer:

 /* sizeof.c—Program to tell the size of the C variable */

 /*      type in bytes */

 

 #include <stdio.h>

 

   int main(void)

  {

  printf( "\nA char   is %d bytes", sizeof( char ));

  printf( "\nAn int   is %d bytes", sizeof( int ));

  printf( "\nA short   is %d bytes", sizeof( short ));

  printf( "\nA long   is %d bytes", sizeof( long ));

  printf( "\nA long long is %d bytes\n", sizeof( long long));

  printf( "\nAn unsigned char is %d bytes", sizeof( unsigned char ));

  printf( "\nAn unsigned int  is %d bytes", sizeof( unsigned int ));

  printf( "\nAn unsigned short is %d bytes", sizeof( unsigned short ));

  printf( "\nAn unsigned long is %d bytes", sizeof( unsigned long ));

  printf( "\nAn unsigned long long is %d bytes\n",

   sizeof( unsigned long long));

 printf( "\nA float   is %d bytes", sizeof( float ));

 printf( "\nA double  is %d bytes\n", sizeof( double ));

 printf( "\nA long double is %d bytes\n", sizeof( long double ));

return 0;

 }

2. #include<stdio.h>

int main(){

  int num,reverse_number;

  //User would input the number

  printf("\nEnter any number:");

  scanf("%d",&num);

  //Calling user defined function to perform reverse

  reverse_number=reverse_function(num);

  printf("\nAfter reverse the no is :%d",reverse_number);

  return 0;

}

int sum=0,rem;

reverse_function(int num){

  if(num){

     rem=num%10;

     sum=sum*10+rem;

     reverse_function(num/10);

  }

  else

     return sum;

  return sum;

}

3.  

#include <bits/stdc++.h>  

 

using namespace std;  

/* Iterative function to reverse digits of num*/

int reversDigits(int num)  

{  

   int rev_num = 0;  

   while(num > 0)  

   {  

       rev_num = rev_num*10 + num%10;  

       num = num/10;  

   }  

   return rev_num;  

}  

 

/*Driver program to test reversDigits*/

int main()  

{  

   int num = 4562;  

   cout << "Reverse of no. is "

        << reversDigits(num);  

   getchar();  

   return 0;

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When you block a number can they still text??
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Explanation:

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The information exchange takes place first by the client by introducing itself to the remote server. the remote server upon receiving the information uses some form of handshaking and acknowledges the client of the receipt of the message.

besides this there are many routing protocols which tells us about the way how packets are sent from the client to the source. There are two types of routing protocols:

1. static routing protocols

2. dynamic routing protocols.

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