Answer:
public static int powOfTwo(int input) {
return input*input;
}
You will have to call this method in main
for printing it, write
System.out.println(powOfTwo(your number));
in public static void main(str[]args) {
}
Sssa rinmmy sihoa ihu hji ishoa io>?
Is this computer science?
If so, then the function you would need for your code is this...
_____
if (someValue%2 != 0) {
value *= -1;
}
_____
//basically <u>number%2 == 0</u> means even so "!" means false so "not even" meaning "odd."
Assuming you are doing an array list (given a set value) or a for-loop with an
int someValue = Integer.parseInt(args[i]); inside (not given a set value and not restricted)
Otherwise ignore me....lol
Answer:
There is an IRQ conflict, and you need to use Device Manager to resolve the problem.
Explanation:
IRQ is a synonym for "interrupt request line" and are lines which devices use to send interrupt signal to the microprocessor of a device. IRQ conflicts usually occur when a new device is added to a PC, and this can be resolved by setting the IRQ number and you can go about this by going using the Device Manager to resolve this.
there are many differences, but the most prominent are that they have different apis (aplication programing interface) and different architecture
also mobile apps tend to use less system resources and are more regulated by services like the google play store, opposed to the fairly unregulated uwp platform used by most windows machines.
