the denominator cannot be zero, because the division by zero is not defined, therefore:
![\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2-9%3D0%20%5C%5C%20%5Ctext%7BSolving%20for%20x%3A%7D%20%5C%5C%20x%5E2%3D9%20%5C%5C%20%5Csqrt%5B%5D%7Bx%5E2%7D%3D%5Csqrt%5B%5D%7B9%7D%20%5C%5C%20x%3D%5Cpm3%20%5Cend%7Bgathered%7D)
Therefore the domain of (f o g)(x) is:
Um, so it's a bit awkward with this question because they actually got the x value incorrect. When they added up all the values, they got 9x - 27 = 180, but it's actually 9x + 27 = 180 because -18 + 45 is positive 27. Anyways, when you solve it correctly you get x = 17, and then you substitute it into the angles. So with 5x - 18, you are saying 5(× 17) - 18 = 67. Then with the other one you do 4(× 17) + 45 = 113. You know that x is definitely 17 because 113 + 67 = 180.
Answer:
Step-by-step explanation:
y - 2 = -2(x - 3)
y - 2 = -2x + 6
y = -2x + 8
Answer:
8- 3x = 2 I think this is
I'm assuming you want an equation with a slope of -5 that also passes through the point (1, -7).
An equation that fits this is
Hope this helps!
