Ask question

Ask question

All categories

3 years ago

5

Solve for x

align="absmiddle" class="latex-formula">+ $\frac{x}{7}$ =−1

2 answers:

g100num [7]3 years ago

8 0

Answer:

$x = -\frac{14}{9}$

I hope this helps!

MaRussiya [10]3 years ago

7 0

$\Large \underline{\tt Given} :$

$\tt \dfrac{x}{2}+\dfrac{x}{7} = - 1$

$\\$

$\Large \underline{\tt To \: Find} :$

Value of x = ?

$\\$

$\Large \underline{\tt Solution} :$

$\tt \dashrightarrow \dfrac{x}{2}+\dfrac{x}{7} = - 1$

$\tt \dashrightarrow \dfrac{7x + 2x}{2\times 7}= - 1$

$\tt \dashrightarrow \dfrac{9x}{14}= - 1$

$\tt \dashrightarrow 9x= - 1\times 14$

$\tt \dashrightarrow 9x= - 14$

$\tt \dashrightarrow x= - \dfrac{14}{9}$

$\\$

$\bf Hence, \:value\: of \: x = - \dfrac{14}{9}$

You might be interested in

Sarah can take no more than 22 pounds and I like the trap her suitcase weighs 112 ounces how many more pounds can she park witho

Leya [2.2K]

Answer:

15 pounds

Step-by-step explanation:

there are 16 ounces in one pound

so...

first find the limit in ounces

$22 = \frac{x}{16}$

because there are 16 ounces in every one pound you need to multiply 22 by 16

which is 352

now subtract what you already used

$352 - 112$

which is 240

now convert to pounds

$x = \frac{240}{16}$

which is 15

so 15 more pounds

3 0

3 years ago

Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi

den301095 [7]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31 or higher are significantly high

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 20.6, \sigma = 5.2$

Significantly low:

Z-scores of -2 or lower

So scores of X when Z = -2 or lower

$Z = \frac{X - \mu}{\sigma}$

$-2 = \frac{X - 20.6}{5.2}$

$X - 20.6 = -2*5.2$

$X = 10.2$

Test scores of 10.2 or lower are significantly low.

Significantly high:

Z-scores of 2 or higher

So scores of X when Z = 2 or higher

$Z = \frac{X - \mu}{\sigma}$

$2 = \frac{X - 20.6}{5.2}$

$X - 20.6 = 2*5.2$

$X = 31$

Test scores of 31 or higher are significantly high

6 0

4 years ago

A. 48 square centimeters

NARA [144]

Answer:48

Step-by-step explanation:

8 0

3 years ago

find the volume of the figure. Round to the nearest hundredth if necessary. (figure is not to scale)

ludmilkaskok [199]

The volume is 336 cubic feet

6x8x3 = 144
8x4x6= 192

144+192=336

6 0

3 years ago

Read 2 more answers

How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

6 0

3 years ago