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mote1985 [20]
3 years ago
5

Integer or simplified fraction:)! help pls<3

Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0

Answer:

\dfrac{f^0}{j^{-3}} =8

Step-by-step explanation:

The question relates to the evaluation of an expression given the values of the variables of the expression;

The given expression is \dfrac{f^0}{j^{-3}}

The values of the terms at which the given expression is to be evaluated are;

f = -4 and j = 2

By plugging in the values, we get;

At f = -4 and j = 2,  \dfrac{f^0}{j^{-3}} = \dfrac{(-4)^0}{2^{-3}}

(-4)⁰ = 1

2⁻³ = 1/8

We get;

\dfrac{f^0}{j^{-3}} = \dfrac{(-4)^0}{2^{-3}} = \dfrac{1}{\left (\dfrac{1}{8} \right )} =8

Therefore;

For \ f = -4 \ and \ j = 2, \ \dfrac{f^0}{j^{-3}} = 8.

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Translate the figure 2 units left and 7 units down.
STALIN [3.7K]

The translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

In the question, we are asked to translate the given figure 2 units left and 7 units down.

In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.

For any point P(x, y) the given rule says that after translation,

P(x, y) becomes P'(x - 2, y - 7).

The coordinates of the given figure are:

A(3,9), B(5,9), C(5,2), and D(1,4).

After translation, these points can be shown as:

A(3,9) becomes A'(1,2).

B(5,9) becomes B'(3,2).

C(5,2) becomes C'(3,-5).

D(1,4) becomes D'(-1,-3).

Thus, the translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

Learn more about translations at

brainly.com/question/1400185

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Please help, Brainliest, thanks and five star
igomit [66]

Answer:

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Step-by-step explanation:

6 0
3 years ago
198 sq.yd. 8 sq. ft. x 7 =
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Answer:

Step-by-step explanation:

Give the data

198 sq.yd × 8 sq ft ×7

Note that we have two unit of measurement which are yd and ft and 7 is just a constant

So we need to convert them,

Then, 1 yd = 3ft

Also notice that they are square.

Then square both sides of the comparison

(1 yd)² = (3 ft)²

1 sq.yd = 9 sq.ft

Then, back to our question,

198 sq.yd × 8 sq ft ×7

Let covert to ft

198 sq.yd× (9 sq.ft/1 sq.yd) ×8 sq.ft×7

sq.yd cancels out

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Let convert to yd

198 sq.yd × 8 sq ft ×7

198 sq.yd×8 sq.ft (1 sq.yd / 9sq.ft )×7

1,232 sq.yd × sq.yd

1,232 yd⁴

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