Question

Integer or simplified fraction:)! help pls<3

Answer 1

Answer:

$\dfrac{f^0}{j^{-3}} =8$

Step-by-step explanation:

The question relates to the evaluation of an expression given the values of the variables of the expression;

The given expression is $\dfrac{f^0}{j^{-3}}$

The values of the terms at which the given expression is to be evaluated are;

f = -4 and j = 2

By plugging in the values, we get;

At f = -4 and j = 2,  $\dfrac{f^0}{j^{-3}} = \dfrac{(-4)^0}{2^{-3}}$

(-4)⁰ = 1

2⁻³ = 1/8

We get;

$\dfrac{f^0}{j^{-3}} = \dfrac{(-4)^0}{2^{-3}} = \dfrac{1}{\left (\dfrac{1}{8} \right )} =8$

Therefore;

$For \ f = -4 \ and \ j = 2, \ \dfrac{f^0}{j^{-3}} = 8.$