Find the perimeter of the<br> polygon if ZB = ZD.

PLEASE HELP SOON I ONLY NEED HELP WITH NUMBER 18 PICTURE IS INCLUDED

anyanavicka [17]

Critical thinking? We're in trouble. It's hard for me to tell what grade this is.

Stem and leaf is fine but let's just write out the data.

Rich: 35 37 41 42 43 44 45 48 50 55 n=10

Will: 42 43 44 44 46 47 47 48 49 50 n=10

Use measures of center and measures of variation ...

The three measures of center typically used are the mean, the median and the mode.

Rich's sum = 440 so Rich's mean = 440/10 = 44

Rich's middle values are 43 and 44 so Rich's median = 43.5

All Rich's scores are unique so he doesn't really have a mode.

Will's sum = 460, Will's mean = 460/10 = 46

Will's middle numbers are 46 and 47 so median 46.5

Will's data has two modes tied, 44 and 47.

OK, so far these say Rich is a better golfer; he has lower mean and median scores than Will. (Low score is better in golf.)

Let's look at measures of variation. I'm guessing that they don't want to you calculate standard deviation. So we'll do range and mean absolute deviation.

The range is max-min.

Rich's range is 55-35=20

Will's range is 50-42=8

Will is more consistent.

Rich's mean is 44, his scores are here; let's calculate absolute deviation:

Score 35 37 41 42 43 44 45 48 50 55

AbsDev 9 7 3 2 1 0 1 4 6 11

Rich's deviations add to 44 so his MAD is 4.4

Will's mean is 46

Score: 42 43 44 44 46 47 47 48 49 50

AbsDev 4 3 2 2 0 1 1 2 3 4

The sum is 22, Will's MAD is 2.2

Based on the measures of variation, Will is a more consistent golfer. He's on average worse than Rich, but he always manages to stay pretty close to his average while Rich is all over the place.

Still I'd go with Rich for the tournament.

7 0

3 years ago

Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x3 − 6x2 − 15x + 2 (a) Find the interval on which

Burka [1]

Answer:

a) $(-\infty, -1) \cup (5, \infty)$

b) $(-1,5)$

Step-by-step explanation:

The first step to solve this question is finding the roots of the derivative of x.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$f(x) = x^{3} - 6x^{2} - 15x + 2$

So

$f'(x) = 3x^{2} - 12x - 15$

Finding the roots:

$3x^{2} - 12x - 15 = 0$

Simplifying by -3

$x^{2} - 4x - 5 = 0$

So $a = 1, b = -4, c = -5$

Then

$\bigtriangleup = (-4)^{2} - 4*1*(-5) = 36$

$x_{1} = \frac{-(-4) + \sqrt{36}}{2} = 5$

$x_{2} = \frac{-(-4) - \sqrt{36}}{2} = -1$

So the function can be divided in three intervals.

They are:

Less than -1

Between -1 and 5

Higher than 5

In which it increases and which it decreases?

Less than -1

Lets find the derivative in a point in this interval, for example, -2

$f'(x) = 3x^{2} - 12x - 15$

$f'(-2) = 3*(-2)^{2} - 12*(-2) - 15 = 21$

Positive.

So in the interval of $(-\infty, -1)$ , the function increases.

Between -1 and 5

Will choose 0.

$f'(x) = 3x^{2} - 12x - 15$

$f'(0) = 3*(0)^{2} - 12*(0) - 15 = -15$

Negative.

So in the interval of $(-1,5)$ , the function decreases.

Higher than 5

Will choose 6.

$f'(x) = 3x^{2} - 12x - 15$

$f'(6) = 3*(6)^{2} - 12*(6) - 15 = 21$

Positive

So in the interval of $(5, \infty)$ , the function increases.

(a) Find the interval on which f is increasing.

Using interval notation

$(-\infty, -1) \cup (5, \infty)$

b) Find the interval on which f is decreasing.

$(-1,5)$

5 0

4 years ago

Talisa plans a 30-foot deep pond. While digging, she hits rock 25 feet down. How can Talisa modify

Natali [406]

9514 1404 393

Answer:

multiply the radius by √1.2 ≈ 1.0954

Step-by-step explanation:

Let the original depth and radius be represented by 30 and r. Let the modified depth and radius be represented by 25 and r'. Assuming the pond is uniform depth, the formula for the volume of a cylinder applies. The volume of a cylinder is given by ...

V = πr²h

In this application, we want the original and modified volumes to be the same.

πr²(30) = π(r')²(25)

(r')² = r²(30/25) = r²(6/5)

r' = r√(6/5)

The radius can be multiplied by √1.2 to maintain the original volume of the pond.

6 0

3 years ago

What is 14 3/4 divide 25

lesantik [10]

Answer:

0.59

Step-by-step explanation:

7 0

3 years ago

Equations & Graphs

alex41 [277]

Answer:

Answer to5)y=3

Answer to q9)x=3

8 0

3 years ago

Read 2 more answers

Find the perimeter of the polygon if ZB = ZD.