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natita [175]
3 years ago
11

2 Which of the following polynomials is not written in standard form?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

3

Step-by-step explanation:

Standard form is written in the order of the exponent <em>on</em><em> </em><em>a</em><em> </em><em>variable</em> from highest to lowest.

#1 exponents go 2, 1 , then zero. So, this is standard form.

#2 exponents go 2 then zero, so this is standard form.

#3 exponents go 1 then 2 then zero, so this is <em><u>not</u></em> in standard form.

#4 exponents go 3 to 2 to 1, so this is still in standard form.

hope this helps!

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Simplify: (k⁴)(k⁷)(k⁰)<br>a.k⁰<br>b.k²⁸<br>c.k¹¹<br>d.k¹²​
attashe74 [19]

Answer:

c.k¹¹

Step-by-step explanation:

Anything raised to the power of 0 is one so k^0=1

k^4k^7

Since they have the same base you can just add them

4+7=11

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3 years ago
How do i solve this?
dangina [55]

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100 points and brainliest The data to represent average test scores for a class of 16 students includes an outlier value of 78.
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Answer:

The mean would Increase.

Step-by-step explanation:

If you take out the low score, then the average score of the class would go up.

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Step-by-step explanation:

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3 years ago
In 2016, the mean score on the AP Art History exam was 3.8, with a standard deviation of 1.2. The mean score on the AP English e
Ulleksa [173]

Answer:

X+Y \sim N(\mu_X +\mu_Y , \sqrt{\sigma^2_X +\sigma^2_Y})

The mean is given by:

\mu = 3.8+2.9= 6.7

And the standard deviation would be:

\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08

And the distribution for X+Y would be:

X+Y \sim N(6.7 , 2.08)

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

Step-by-step explanation:

Let X the random variable who represent the AP Art History exam we know that the distribution for X is given by:

X \sim N(3.8, 1.2)

Let Y the random variable who represent the AP English exam we know that the distribution for X is given by:

X \sim N(2.9, 1.7)

We want to find the distribution for X+Y. Assuming independence between the two distributions we have:

X+Y \sim N(\mu_X +\mu_Y , \sqrt{\sigma^2_X +\sigma^2_Y})

The mean is given by:

\mu = 3.8+2.9= 6.7

And the standard deviation would be:

\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08

And the distribution for X+Y would be:

X+Y \sim N(6.7 , 2.08)

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

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3 years ago
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