Answer:One solution was found : x = 12. Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the ...
Step-by-step explanation:
Answer:
(x+2)(x+1)
Step-by-step explanation:
Assuming im interpreting this correctly, it should be (x+2)(x+1), since if you plug in -2 and -1, it will give you 0, which is the answer.
Answer:
7/15
Step-by-step explanation:
Well 4/5 - 1/3 = 12 / 15 - 5 / 15 which is equal to 7/15, but there aren't any expressions in your question.
<h3>
Answer: Choice B</h3>
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Explanation:
The rule we use is
![\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m](https://tex.z-dn.net/?f=%5CLarge%20a%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20%5Cleft%28%5Csqrt%5Bn%5D%7Ba%7D%5Cright%29%5Em)
where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).
So for instance,
![\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3](https://tex.z-dn.net/?f=%5CLarge%202%5E%7B3%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7B2%5E3%7D%20%3D%20%5Cleft%28%5Csqrt%5B4%5D%7B2%7D%5Cright%29%5E3)
or in this case,
![\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5](https://tex.z-dn.net/?f=%5CLarge%20t%5E%7B5%2F8%7D%20%3D%20%5Csqrt%5B8%5D%7Bt%5E5%7D%20%3D%20%5Cleft%28%5Csqrt%5B8%5D%7Bt%7D%5Cright%29%5E5)
Answer:
The value of currents are
,
and
.
Step-by-step explanation:
The Ohm's law states that

it is given that the V₁=3V and V₂=4V.
In a parallel circuit:
- Voltage is same in each component
- Sum of the currents equals to the total current that flows.
.... (1)
Equation for first loop is,

..... (2)
Equation for second loop is,

..... (3)
On solving (1), (2) and (3) we get



Therefore the value of currents are
,
and
.