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ValentinkaMS [17]
3 years ago
7

7/8 subtracted by 2/7

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0

Find common denominators.

7/8 = 49/56

2/7 = 16/56

Subtract.

49/56 - 16/56 = 33/56

The fraction cannot be simplified any further.

Best of Luck!

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GarryVolchara [31]

Answer:One solution was found : x = 12. Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the ...

Step-by-step explanation:

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Which of the following is equal to the rational expression when x -2 or -1? x^2-4/(x+2)(x+1)
Orlov [11]

Answer:

(x+2)(x+1)

Step-by-step explanation:

Assuming im interpreting this correctly, it should be (x+2)(x+1), since if you plug in -2 and -1, it will give you 0, which is the answer.

8 0
3 years ago
Which expression is equivalent 4/5 - 1/3?
BARSIC [14]

Answer:

7/15

Step-by-step explanation:

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Read 2 more answers
Which radical expression in the picture is equivalent to t^5/8?
mixas84 [53]
<h3>Answer: Choice B</h3>

=========================================================

Explanation:

The rule we use is

\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m

where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).

So for instance,

\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3

or in this case,

\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5

5 0
2 years ago
Determine the currents in the picture
Elenna [48]

Answer:

The value of currents are I_1=0A, I_2=1A and I_3=1A.

Step-by-step explanation:


The Ohm's law states that

V=IR

it is given that the V₁=3V and V₂=4V.

In a parallel circuit:

  • Voltage is same in each component
  • Sum of the currents equals to the total current that flows.

I_2=I_1+I_3                   .... (1)

Equation for first loop is,

V_1=4I_1+3I_2

3=4I_1+3I_2              ..... (2)

Equation for second loop is,

V_2=1I_3+3I_2

4=1I_3+3I_2             ..... (3)

On solving (1), (2) and (3) we get

I_1=0


I_2=1

I_3=1

Therefore the value of currents are I_1=0A, I_2=1A and I_3=1A.

6 0
3 years ago
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