15 gallons of 35% peroxide solution contains 0.35 × 15 = 5.25 gallons of hydrogen peroxide. The rest of the volume is made up of 15 - 5.25 = 9.75 gallons of water.
If we add
gallons of water to the solution, the amount of hyrdrogen peroxide in the solution stays the same, but the volume of water increases to
gallons, and the total volume increases to
gallons.
To get a concentration of 8% in this diluted solution, we add
gallons of water such that

Solve for
.




To get the desired concentration, one must add 50.625 gallons of water, and one will end up with a total volume of 65.625 gallons of solution.
Since all triangles r equal to 180°
123+41= 164
180-164=16
the measure of the third angle of the triangle is 16°
Answer:
<u>14.96</u>
Step-by-step explanation:
6*84p=504p
504p=£5.04
£20-£5.04=14.96
Lateral Cone Area = PI * radius * slant height
slant height ^ 2 = 6^2 + 10^2
slant height ^ 2 = 36 + 100
slant height ^ 2 = 136
slant height ^ 2 = 11.6619037897
Lateral Cone Area = PI * 6 * 11.66
Lateral Cone Area = 219.6744
That's my calculation and I used an online calculator which says the same thing. It is NOT one of the choices.
online calculator 1728.com/volcone.htm
I normally use a graphing calculator, but if you need to graph by hand I normally make a table with the x-values of -5 to 5 and plug in those range of x-values to graph the dots on the plot.
For example, if the function was
, I would want to start with a table, and plug in my x-values to given formula as I go through each x.
x = -5 then y = 
x = -4 then y = 
x = -3 then y = 
x = -2 then y = 
x = -1 then y = 
x = 0 then y = 0
x = 1 then y = 
x = 2 then y = 
x = 3 then y = 
x = 4 then y = 
x = 5 then y = 
Of course you don't have to use for the x-values -5 to 5 if it's too long. At least 5 points should be made on the graph to improve accuracy. Other things like max, min, y-intercept, slope, x-intercept, etc all matter when graphing but if you were to just look at how to draw the basic functions first and how they look like, everything else will come naturally.
Now that the table of x and y values are made, you just need to plot this on a graph and connect the dots. The rest of the graph can be sketched to be an estimate of what the other values of x would possibly be equal to. As long as the bottom points of
is complete and accurate the rest is drawn as close as you can make it, if that makes sense...
Hope that helps!