Let's check the dot product .
v.w = 5(4)-2(10) = 20 -20 =0
So the dot product is not 20 . And since the dot product is zero, so they are perpendicular.
And the y component of w is 10.
So correct options are first and third .
This question is worded badly, so don't be alarmed.
Obviously if this were a square patter the number of red tiles could only be 1,4,9,16,25,36 etc and this is not the numbers given...It would help tremendously if they gave you another reference point so as to know how the tiles were being laid out.
If they are laid out alongside one another with a consistent border for each you wouldn't need 12 blue tiles for each red tile either...if two were laid side by side you would only need 20 blue tiles to have the border around both...you see how the arrangement makes a huge difference and you are given no details as to what that arrangement is...
So just to keep it simple, assume that each red tile is surrounded by 12 blue tiles....
Total tiles equals r+12r=13r
t=13r so
t(15)=195, t(20)=260, t(25)=325, t(30)=390
Product = multiply
(6x-y)*(2x-y+2) =
12x^2 -8xy + 12x + y^2 - 2y
Answer:
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Answer:
11 rides
Step-by-step explanation:
let the total amount be y
and let the number of ride be x
the expression for the situation is y=mx+c
given
total amount=$28
admission fee= $6
cost per ride=$2
we are expected to find x
substitute into the expression we have
28=2x+6
28-6=2x
22=2x
divide boths sides by 2 we have
x=22/2
x=11
the number of rides is 11