Answer:
Hey mate here is your answer...
Step-by-step explanation:
smaller circular table to be made
with a diameter only half as big... and diameter of big table is (2*55)= 110cm.... So half diameter of big is (110/2)= 55cm
therefore, diameter of smaller table is 55cm and radius of it's (55/2)= 27.5cm
circumference of circle = 2πr
= 2*3.14*27.5
= 172.7 cm = 27.5cm
hope it helps you ❣️
Answer:
Step-by-step explanation:
Answer:
x = -14/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
x + 2/3 = -4
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract 2/3 on both sides: x = -14/3
Here 'a' corresponds to 0.
Now there are two possibilities for 'r' & 't'
Case 1.
They are on the same side to the right of 'a'
In that case 'r' corresponds to 5 & 't' corresponds to 7.
The midpoint of 'r' and 't' shall be 
Case 2.
Both are on the left of 'a'.
In that case 'r' corresponds to -5 & 't' corresponds to -7
The midpoint shall be 
Case 3.
'r' in on the right of 'a' and 't' is on the left of 'a'
So 'r' corresponds to 5 and 't' corresponds to -7
The midpoint shall be 
Case 4.
'r' is on the left of 'a' & 't' is on the right of 'a'.
'r' corresponds to -5 & 't' corresponds to 7
The midpoint shall be 
The possible coordinates of the midpoints of rt are 6, -6, 1, -1.
Answer:
Class 7A collected 4.8 ounces of pure gold.
Step-by-step explanation:
<u>Key skills required are: Percentages, Multiplication</u>
<u />
- We only need the information about Class 7A. They collected 40 oz that contains 12% gold.
- In other words, this means that 12% of that 40 oz gold sand is pure gold.
Here we have to do 12% x 40 to find the number of oz of pure gold. We first have to convert 12% into a decimal. Divide it by a 100 (or move the decimal point 2 places to the left) and you will get 0.12.
<em>Do 0.12 x 40 and you will get 4.8</em>
Therefore, there are 4.8 oz of pure gold in Class 7A's gold sand
