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2 years ago

Seventh graders collected some gold sand on a class field trip.

Mathematics

1 answer:

satela [25.4K]2 years ago

3 0

Answer:

Class 7A collected 4.8 ounces of pure gold.

Step-by-step explanation:

Key skills required are: Percentages, Multiplication

We only need the information about Class 7A. They collected 40 oz that contains 12% gold.
In other words, this means that 12% of that 40 oz gold sand is pure gold.

Here we have to do 12% x 40 to find the number of oz of pure gold. We first have to convert 12% into a decimal. Divide it by a 100 (or move the decimal point 2 places to the left) and you will get 0.12.

Do 0.12 x 40 and you will get 4.8

Therefore, there are 4.8 oz of pure gold in Class 7A's gold sand

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3 years ago

What value of p will make the expression below a perfect square? x^2 - x + P

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Answer:

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Step-by-step explanation:

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3 years ago

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2 years ago

For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r < d. n = −67, d = 8

Firlakuza [10]

Answer:

$q = 8$

$r = 3$

Step-by-step explanation:

Given

$n = dq + r$

$0 \le r < d$

$n = 67$ --- not -67

$d = 8$

Required

Find q and r

Substitute values for d and b

$n = dq + r$

$67 = 8 * q + r$

$67 = 8q + r$

Make q the subject

$q = \frac{67 - r}{8}$

$0 \le r < d$ means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let $r = 3$

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No other true values of r and q can be gotten.

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3 years ago

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3x + 5y = 0
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x = -5y/3
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3x + 5y = 0
Add -3 to both sides.
5y = -3x
Divide both sides by 5.
y = -3/5x

I Sure Hope This Helps!

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3 years ago