Your pay is described by a piecewise function p(t) where t is hours worked.
![p(t)=\left\{\begin{array}{rcl}7t&\mbox{for}&t\leq40\\10.5t-140&\mbox{for}&t>40\end{array}\right.](https://tex.z-dn.net/?f=p%28t%29%3D%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Brcl%7D7t%26%5Cmbox%7Bfor%7D%26t%5Cleq40%5C%5C10.5t-140%26%5Cmbox%7Bfor%7D%26t%3E40%5Cend%7Barray%7D%5Cright.)
The domain of this function is the number of hours you can work in a week—zero to 168. The range is the set of values p(t) can take on, which we have said is p(0) to p(168). This problem, however, is asking for the range for a typical 40-hour week. That will be p(0) to p(40):
the interval [0, 280].
Answer:
C
Step-by-step explanation:
substitute -1 into all of the formulas, if both sides are equal, then it is correct, for C:
2(x-2)+6 = 0, sub -1
2(-1-2)+6=0, simplify and work out
2(-3)+6=0
-6+6=0
0=0
The lowest common denominator is lcm(5, 3), which is 15.
The sum of 2/5 + 5/3 + 9/3 is 6/15 + 25/15 + 45/15, which is 76/15 or
.
△ABC~<span>△YZX
You just figure out what sides are similar to each other
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