Solve for x 2x+3≥−1 Please

Mathematics

2 answers:

elena-s [515]3 years ago

5 0

Answer:

x ≥ -2

Step-by-step explanation:

$2x+3\geq-1\\2x\geq-4\\x\geq-2$

gogolik [260]3 years ago

5 0

$2x + 3 \geqslant - 1 \\ 2x \geqslant - 3 - 1 \\ 2x \geqslant - 4 \\ x \geqslant \frac{ - 4}{2} \\ x \geqslant - 2$

You might be interested in

Factorize no i, l, o

Mademuasel [1]

Answer:

here ,

question no. L the question is incomplete.

rest all are solved hope this helped u ☺️

3 0

3 years ago

What is 14% of 3.09 million

svlad2 [7]

14% * 3.09 million = 432,600

7 0

3 years ago

Find the sum of the convergent series 7 0.7 0.007

mafiozo [28]

$7+0.7+0.007+\cdots=7\left(1+\dfrac1{10}+\dfrac1{100}+\cdots\right)$

Let $S_n$ denote the $n$ th partial sum of the series, i.e.

$S_n=1+\dfrac1{10}+\dfrac1{100}+\cdots+\dfrac1{100^n}$

Then

$\dfrac1{10}S_n=\dfrac1{10}+\dfrac1{100}+\dfrac1{1000}+\dfrac1{10^{n+1}}$

and subtracting from $S_n$ we get

$S_n-\dfrac1{10}S_n=\dfrac9{10}S_n=1-\dfrac1{10^{n+1}}$
$\implies S_n=\dfrac{10}9\left(1-\dfrac1{10^{n+1}}\right)$

As $n\to\infty$ , the exponential term vanishes, leaving us with

$\displaystyle\lim_{n\to\infty}S_n=\dfrac{10}9$

and so

$7+0.7+0.007+\cdots=7.777\ldots=\dfrac{70}9$