C=(1/4)*circumference
Area=pq+3.142r^2
60*3.142=pq+3.142p^2
q=((1/4)*2p*3.142)+2*3.142
q=1.571p+6.284
188.52=1.571p^2+6.284p+3.142p^2
188.52=4.713p^2+6.284p
188520=4713p^2+6284p
Answer:
(40 x 50) + (40 x 1) + (2 x 50) + (2 x 1) = 2,000 + 40 + 100 + 2
the width of Yun's area model is 7x units or ( x-2 )units .
<u>Step-by-step explanation:</u>
Here we have , Yun was trying to factor 7x^2-14x. He found that the greatest common factor of these terms was 7x and made an area model: What is the width of Yun's area model. Let's find out:
We know that area of rectangle :
⇒ 
.........(1)
Now , According to question we have
⇒ 
⇒ 
Comparing this equation to equation (1) we get that :
⇒ 
or , 
Therefore , the width of Yun's area model is 7x units or ( x-2 )units .
Answer:
- 740 meters of fence
- 22,000 square meters
Step-by-step explanation:
Two of the sides total 150 +220 = 370 meters. The other two sides are the same lengths, so the sum of lengths of the four sides is ...
2·370 m = 740 m . . . . . length of fence needed
__
The area of a parallelogram is the product of base and height.
A = bh = (220 m)(100 m) = 22,000 m^2 . . . . area the fence encloses
C. 25
——-
Divide 400/100=4
——-
Than divide 4/100
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