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Lera25 [3.4K]
3 years ago
12

Help with number 17 plz!

Mathematics
1 answer:
love history [14]3 years ago
5 0

Answer:

  • 740 meters of fence
  • 22,000 square meters

Step-by-step explanation:

Two of the sides total 150 +220 = 370 meters. The other two sides are the same lengths, so the sum of lengths of the four sides is ...

  2·370 m = 740 m . . . . . length of fence needed

__

The area of a parallelogram is the product of base and height.

  A = bh = (220 m)(100 m) = 22,000 m^2 . . . . area the fence encloses

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we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to
Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

42% of freshmen do not visit their counselors regularly.

This means that \pi = 0.42

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}

0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}

\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2

n = 1076.8

Rounding up:

A sample of 1077 is required.

3 0
3 years ago
the following histogram shows the number of days during the school year that students bought lunch. How many total students are
olga2289 [7]
You have to post a picture of the actually histogram we can’t see it
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2 years ago
Bob is a realtor who specializes in high-end properties. In an advertising campaign, he wants to point out that his properties a
madreJ [45]

Answer:

D.

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8 0
3 years ago
Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent
Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly  among the given student the probability that this student is wearing a ring or necklace is

P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1

P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4

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Therefore the required probabilty is 0.4

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3 years ago
A quadrilateral has two consecutive angles that measure 90 degrees each
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The answer is C)i, ii, iii, iv


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