what is the external net force exerted on a 3.5 kg papaya which is being pushed across a table and has an acceleration of 2.2 m/
1 answer:
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Answer:
95
Step-by-step explanation:
let x be his mark in the fourth test, then
mean = = 83 ( multiply both sides by 4 )
83 + 81 + 73 + x = 332
237 + x = 332 ( subtract 237 from both sides )
x = 95