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Gnoma [55]
3 years ago
8

Use a commutative property to complete the statement. ba=

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0
Is that the full question
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Write the subtraction fact 10-3 two ways
lisabon 2012 [21]
10-3 or 10+(-3) that should help
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3 years ago
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Find the fifth roots of 32(cos 280° + i sin 280°)
shusha [124]

Answer:

The fifth root is 2[cos(56°) + i sin(56°)]

Step-by-step explanation:

* To solve this problem we must revise De Moiver's rule

- In the complex number with polar form

∵ z = r(cosФ + i sinФ)

∴ z^n = r^n(cos(nФ) + i sin(nФ))

* In the problem

- The fifth root means z^(1/5)

- We can put 32 as a form a^n

∵ 32 = 2 × 2 × 2 × 2 × 2 = 2^5

∴ z = 2^5[cos(280°) + i sin(280°)]

* Lets find z^(1/5)

*z^{\frac{1}{5}}=[2^{5}]^{\frac{1}{5} } (cos(\frac{1}{5})(280)+isin(\frac{1}{5})(280)

*(2^{5})^{\frac{1}{5}}=2^{5.\frac{1}{5}}=2

∴ z^(1/5) = 2[cos(56) + i sin(56)]

* The fifth root of 32[cos(280°) + i sin(280°)] is 2[cos(56°) + i sin(56°)]

 

4 0
3 years ago
Find the distance between the origin and the point R = (9,7,8). The distance is: Ensure that you use at least 4 decimal place ac
gregori [183]

Answer:

The distance between the origin and the given point is 13.9283 units.  

Step-by-step explanation:

The coordinates of origin are (0,0,0)

We are given a point R(9,7,80

The distance formula:

\sqrt{(y_1 -x_1)^2 + (y_2 -x_2)^2 + (y_3 -x_3)^2}, where (x_1, x_2, x_3) are coordinates of one point and  (y_1, y_2, y_3) are coordinates of other point.

Putting the values as:

y_1 = 9, y_2 = 7, y_3 = 8\\x_1 =0, x_2 = 0, x_3 = 0

We get d = \sqrt{81 + 64 + 49}

d = \sqrt{194}

d = 13.9283

Thus, the distance between the origin and the given point is 13.9283 units.

8 0
4 years ago
Suppose that you can buy 5 apples for $2. How much would it cost to<br> buy 17 apples?
Doss [256]
69420 apples all together
7 0
3 years ago
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what is the standard form of the equation of a circle with the center 16,4 and a radius of 2 radical 2
Stella [2.4K]

Answer:

(x - 16)² + (y - 4)² = 8

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (16, 4) and r = 2\sqrt{2}, thus

(x - 16)² + (y - 4)² = (2\sqrt{2} )², that is

(x - 16)² + (y - 4)² = 8

6 0
3 years ago
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