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fomenos
2 years ago
12

I need help!! thnaks

Mathematics
1 answer:
liraira [26]2 years ago
3 0

Answer:

7a + 2b

Step-by-step explanation:

Given

4a + 3b + 3a - b ← collect like terms

4a + 3a + 3b - b

= 7a + 2b

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A company has two manufacturing plants with daily production levels of 9 x plus 14 items and 7 x minus 5 ​items, respectively. T
RUDIKE [14]

Answer:

3x+14

Step-by-step explanation:


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3 years ago
A horse-drawn carriage tour company has found that the number of people that take their tour depends on the price charged per cu
Gennadij [26K]
P(2)×c(2) = 76×60 = 4560 is the revenue the company can expect when the charge per customer is 2×$5 above a rate of $50 per person, that is, $60 per person.

The 1st selection is appropriate
7 0
3 years ago
Approximate the value of V61 to the nearest hundredth.<br><br> No links please!
Nookie1986 [14]
The answer above is scam. They just tyr to get potns. The correct andwr dos 3736.
6 0
2 years ago
Susan learns that 6% of the freshman class are in the band, 11% are in the chorus, and 19% are in sports. If no freshman is part
Blizzard [7]
Add the percent values: 6+11+19 = 36

So 36% represents the combined count of people in band, chorus, or sports (no one student is taking more than one class)

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So that's why the answer is choice C) 1/3
6 0
3 years ago
Please help I’ll mark you as brainliest if correct!
AysviL [449]

Step-by-step explanation:

x = number of quarters.

y = number of dimes.

z = number of pennies.

0.25x + 0.1y + 0.01× = 1.05

but it is not possible to find a combination of a subset of the coins to create exactly 1 (= the change for $1).

like to have only 3 quarters and 3 dimes (and no pennies). that makes $1.05, and no combination can create exactly $1.

as a consequence

x < 4 (because 4 quarters is $1, and more than 4 quarters is already more than $1.05).

z < 5 (because with 5 or more pennies, since the total sum is $1.05, if I simply remove 5 pennies, I get $1 with the other coins, no matter what combination they are).

with 1 or 2 or 3 or 4 pennies I cannot build a total sum of $1.05, as the other coins will can only build a sum that ends in 0 or in 5.

so, the sum of these other coins and 1, 2, 3, 4 pennies can never end in 5.

that means, we have 0 pennies.

that rules out to have 0 or 2 quarters, because then together with the dimes the sum can only end in 0 (and actually also give change for $1).

so, we can have only 1 or 3 quarters.

that means the solutions are

1 quarters and 8 dimes

or

3 quarters and 3 dimes.

1 quarter and 8 dimes (and 0 pennies) is the desired solution, because it contains more coins.

for the maximum amount of money built by coins not providing change for $1 we need to remember :

4 quarters are $1 (and would provide change for $1). so, we always need less than 4 quarters. but also at least 1 quarter to keep the sum from ending with a 0 (which would allow again to build $1).

10 dimes are $1 (and provide change for $1). we always need less than 10 dimes.

5 or more pennies would always allow to take away or fill up to create a sum that ends in 0 and therefore build $1. so, we always need less than 5 pennies.

that means again

1 or 3 quarters

max. 9 dimes

4 pennies.

if the the maximum possible sum would be higher than 1.19, then we could only increase in steps of 0.10 (dimes) : 1.29, 1.39, ...

if the sum is 1.29, I could remove 1 quarter and 4 pennies to make $1.

if it is 1.39, I could remove 1 quarter, 1 dime and 4 pennies to make $1.

and so on.

any sum >= 1 created incl. 4 or more quarters or 10 or more dimes or 5 and more pennies can always be reduced to a full $1.

$1.19 can only be built by 1 quarter and 9 dimes and 4 pennies, so that we cannot build $1 out of a subset, or by 3 quarters, 4 dimes and 4 pennies.

and 1 quarter, 9 dimes and 4 pennies has more coins.

7 0
2 years ago
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