This is the question:
A
bicycle manufacturing company makes a particular type of bike.
Each
child bike requires 4 hours to build and 4 hours to test.
Each
adult bike requires 6 hours to build and 4 hours to test.
With
the number of workers, the company is able to have up to 120 hours of building
time and
100 hours of testing time for a week.
If
c represents child bikes and a represents adult bikes,
determine
which system of inequality best explains whether the company can build 10 child
bikes and 12 adult bikes in the week
Now you
can state the system of inequalities from the statements
1) First inequality based on the hours availble
to buiding
Each
child bike requires 4 hours, e<span>ach
adult bike requires 6 hours to build and </span>the company is able to have up to 120 hours of building =>
4c + 6a ≤ 120
2) Second inequality based of the hours available to testing.
Each
child bike requires 4 hours to test, each
adult bike 4 hours to test and the company is able to have up 100 hours of testing time for a week =>
4c + 4a ≤ 100
Then the two inequalities are:
4c + 6a ≤ 1204c + 4a ≤ 100<span>
The answer is Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100Which you can verify by replacing in both equations 10 for c and 12 for a. Look:
1) 4(10) + 6(12) = 40 + 72 = 112 ≤ 1202) 4(10) + 4(12) = 40 + 48 = 88 ≤ 100</span>
Answer:
y=7600(5^(t/22))
Step-by-step explanation:
This is going to be an exponential function as it grows rapidly.
This type of question can be solved using the formula y=a(r^x), where a is the inital amount, r the factor by which the amount increases and x is the unit of time after which the amount increases.
x=t/22
a=7600
r=5
∴y=7600(5^(t/22))
Answer:
I think it's B I hope this is the right answer.
Answer:
A
Step-by-step explanation:
Answer:
It decreases.
Step-by-step explanation:
10 / d
Lets say that it was 10 / 40, which is 10 divided by 40, 0.25.
Now, it has increased to twice the amount of that.
1 / 80, 10 divided by 80, which is 0.125
So, it decreases.
