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kondor19780726 [428]
3 years ago
8

Ann took a taxi home from the airport. The taxi fare was $2.10 per mile, and she gave the driver a tip of $5. Ann paid a total o

f $49.10.
Write an equation to determine the distance in miles (x) between the airport and Ann's home
Find the distance between the airport and Ann's home.
Mathematics
1 answer:
adell [148]3 years ago
3 0

Answer:

$2.10x + 5= $49.10

x=21

Step-by-step explanation:

the x is used for a variable that changes and in this case the mph changes which lead x being the amount of miles that they had drove which at the end ends up multi. with the $2.10 . as for the 5 it was an initial as in it doesn't change.

for the second part

you subtract 5 from each side so you have the total of 2.10x= 44.10 then u divide 2.10 from each side and that will give you x = 21

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If michelle walked 5 meters, how many inches did she walk
DerKrebs [107]
1 meter = 39.370 inches.....so 5 meters = (5)(39.370) = 196.85 inches
4 0
3 years ago
Read 2 more answers
Jones assembles 200 relays in the same time that Smith assembles 180. When Jones has completed 300 relays, how many will Smith h
Finger [1]

Answer:

270

Step-by-step explanation:

Jones turns out 200 relays to Smith's 180. You set up that basic ratio and make a proportion out of it.

S/J = 180/200

Now you make your proportion

S/J = x/300

But the 2 ratios much remain the same.

180/200 = x / 300                  Multiply both sides by 300

180*300/200 = x                    Multiply the numerator together.

54000/200 = x                       Do the division

270 = x

Smith will have turned out 270 relays.

4 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
PLZ HELP ME I NEED HELP
soldier1979 [14.2K]

Answer:

Q: 160 R: 504 S: 480 T: 130 other answer: C

Step-by-step explanation:

6 0
3 years ago
Helpdisdalastquestio
Elis [28]
3 times 96 = 288
3 times 204 = 612
612-288=324
which is approximately $300
5 0
3 years ago
Read 2 more answers
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