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german
3 years ago
9

Tao uses elimination to solve the following system of linear equations.

Mathematics
2 answers:
olasank [31]3 years ago
8 0

Answer:

(0,4) or A

Step-by-step explanation:

Edge 2021

Wewaii [24]3 years ago
5 0

Given:

The system of equation is:

-2x+4y=16

2x+2y=8

To find:

The solution of the given system of equations.

Solution:

We have,

-2x+4y=16              ...(i)

2x+2y=8                ...(ii)

Add (i) and (ii) to eliminate the variable x.

6y=24

y=\dfrac{24}{6}

y=4

Putting y=4 in (ii), we get

2x+2(4)=8

2x+8=8

2x=8-8

2x=0

Divide both sides by 2.

x=0

Therefore, the solution of given system of equations is (0,4). Hence, the correct option is A.

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Serga [27]
-4 (x - 5) + 3 (a - 7)

First, expand your problem. / Your problem should look like: -4x + 20 + 3a - 21
Second, simplify. / Your problem should look like: -4x + 3a - 1

Answer: -4x + 3a - 1 (C)

8 0
4 years ago
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Please give me the correct answer.Only answer if you're very good at math.​
GaryK [48]

Answer:

-9 = 0.45m

Step-by-step explanation:

0.45m - 9 = 0.9m

  • ^ Subtract 0.45m from BOTH sides. so 0.9m - 0.45m... etc
  • Why? So that we can make the equation less complicated. Our goal is to isolate the variable m to be on one side of the "=" sign by itself
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3 years ago
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PLEASE HELP
galben [10]

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4 0
3 years ago
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What is the 9th term of the following geometric sequence? 7/9,-7/3,7,-21,63 ??????
dmitriy555 [2]

Given:

The geometric sequence is:

\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...

To find:

The 9th term of the given geometric sequence.

Solution:

We have,

\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...

Here, the first term is:

a=\dfrac{7}{9}

The common ratio is:

r=\dfrac{a_2}{a_1}

r=\dfrac{\dfrac{-7}{3}}{\dfrac{7}{9}}

r=\dfrac{-7}{3}\times \dfrac{9}{7}

r=-3

The nth term of a geometric sequence is:

a_n=ar^{n-1}

Where, a is the first term and r is the common ratio.

Substitute a=\dfrac{7}{9},r=-3,n=9 to find the 9th term.

a_9=\dfrac{7}{9}(-3)^{9-1}

a_9=\dfrac{7}{9}(-3)^{8}

a_9=\dfrac{7}{9}(6561)

a_9=5103

Therefore, the 9th term of the given geometric sequence is 5103.

5 0
3 years ago
I have four dogs whose average weight is 63 pounds. I also have three cats. The average weight of all seven of my animals is 41
Brums [2.3K]

Answer: 11.67 pounds

Step-by-step explanation:

From the question, the person have four dogs whose average weight is 63 pounds. Then, the total weight of the dogs will be:

= 63 pounds × 4

= 252 pounds

There are also three cats and the average weight of all seven of my animals is 41 pounds. This means that the total animals have a title weight of:

= 41 pounds × 7

= 287 pounds.

To get the weight of the cats, we subtract the total dog's weight from that of the whole animals. This will be:

= 287 - 252

= 35 pounds.

Since there are 3 cats, their average weight will be:

= 35/3

= 11.67 pounds

The average weight of the cats is 11.67 pounds.

8 0
3 years ago
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