<h2><em>Find the LCD of 1/3 and 1/2.</em></h2><h2><em>The LCD is 6.</em></h2><h2><em>1/3 in 6ths is 2/6.</em></h2><h2><em>1/2 in 6ths is 3/6.</em></h2><h2><em>2/6 + 3/6 = 5/6.</em></h2><h2><em>1/3 + 1/2 = 5/6.</em></h2><h2><em>Hope this helps and have a nice day.</em></h2>
She saved up a total of $82.60, and had to spend a total of $60.90, so she would have $21.70 left and need to save up another $180.40, hope this helps
Answer: in explanation
Step-by-step explanation
Sandi can perform 1/9 of the task in a day
Eva can perform 1/5 of the task in a day
Working together, they can perform
1/9 + 1/5 of the task per day
= 5/45 + 9/45 = 14/45 of the task in a day
or 45/14 days in the task = 3.2 days
So
It would take about 3.2 days to complete the task working togethe
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.

c)The expected number of grams to be eaten before encountering the first fragments :
s