<u>Given</u>:
Line m is parallel to line n.
The measure of ∠1 is (4x + 15)°
The measure of ∠2 is (9x + 35)°
We need to determine the measure of ∠1
<u>Value of x:</u>
From the figure, it is obvious that ∠1 and ∠2 are linear pairs.
Thus, we have;
Substituting the measures of ∠1 and ∠2, we get;
Thus, the value of x is 10.
<u>Measure of ∠1:</u>
The measure of ∠1 can be determined by substituting x = 10 in the measure of ∠1
Thus, we have;
Thus, the measure of ∠1 is 55°
73/4 is the answer to your question sir your welcome
It has a width of 35 feet.
*You just subtract the perimeter by the length/width and in this situation you subtract the length*
The answer to your question is false
I did the PEMDAS method (P= parentheses, E= exponents, M= multiplication, D = Division, A= addition, S = subtraction.)
First I did what’s inside the parentheses, (6x2) and got 12.
Then I divided 16 by 22 and received 0.72.
I added 0.72 with 12 and the result was 12.72.
Last step was to subtract 12.72 - 8 and that equals 4.72