Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
A U B = {1, 2, 3, 4, 5, 6, 7}
Step-by-step explanation:
- Step 1: Find A U B. Union of two sets A and B are the set of all elements in set A and set B.
A = {1, 2, 5, 7} and B = {3, 4, 6, 7}
A U B = {1, 2, 3, 4, 5, 6, 7}
First you have to find a common denominator which is 4.
6 2/4 + 3 1/4 = 9 3/4
So your final answer is 9 3/4
Hope this helps!!!!
Let's solve for x ~
Therefore, the possible values of x are 0 and 3
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