The question is attached please help

Mathematics

1 answer:

Maksim231197 [3]3 years ago

7 0

Answer:

area = 102 ft²

Step-by-step explanation:

(8x6) + (9x6) = 48 + 54 = 102 ft²

You might be interested in

Multistep Sandy charges each family that she babysits a flat fee of $10 for the night and an extra $5 per child.kimmi charges $2

Llana [10]

N= night c= child
sandy= $10+$5c
kimmi= $25n
if sandy babysits 3 children for one night they will both be the same price
sandy= $10+5(3)=$25
kimmi= $25

5 0

3 years ago

Read 2 more answers

Need a little help here pls

Crank

Answer:

The statements that must be true are:

XY and JK form four right angles ⇒ B

XY ⊥ JK ⇒ C

JP = KP ⇒ E

m∠JPX = 90° ⇒ F

Step-by-step explanation:

From the given figure

∵ Line XY is the perpendicular bisector of the line segment JK

→ That means line XY is the line of symmetry of the line segment JK

∴ XY ⊥ JK ⇒ C

∵ XY ∩ JK at point P

∴ P is the midpoint of JK

∵ XY ⊥ JK

∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles

∴ XY and JK form four right angles ⇒ B

∵ The measure of the right angle is 90°

∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°

∴ m∠JPX = 90° ⇒ F

∵ P is the midpoint of JK

∴ JP = KP ⇒ E

4 0

3 years ago

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$