Answer:
6q
Step-by-step explanation:
multiply 6 and q
you get 6q
or
q+q+q+q+q+q
you get
6q
Answer:
the answer would be 6 cuz its half of 12
Step-by-step explanation:
it is 12 because the possibility of it landing on 12 is not that big but if u half it like i said it will be a 50/50 that u will land on 6
Answer:
absolutely
Step-by-step explanation:
if you run for one min., you burn 8 calories right?
so if you run for example 10 mins., you would burn 80 calories
80>8
so yes
Given: 120 & 360
Find:
Least
common multiple of 120 and 360
Solution:
In order to use the number patterns to find the least common
multiple of 120 and 360, we need to factor each value first and then, we choose
all the factors that appear in any of the column and then we multiply them.
<span>
<span><span>
<span>
120:
</span>
<span>
2
</span>
<span>
2
</span>
<span>
2
</span>
<span>
3
</span>
<span>
</span>
<span>
5
</span>
</span>
<span>
<span>
360:
</span>
<span>
2
</span>
<span>
2
</span>
<span>
2
</span>
<span>
3
</span>
<span>
3
</span>
<span>
5
</span>
</span>
<span>
<span>
LCM:
</span>
<span>
2
</span>
<span>
2
</span>
<span>
2
</span>
<span>
3
</span>
<span>
3
</span>
<span>
5
</span>
</span>
</span></span>
Therefore, the Least Common Multiple (LCM) of 120 and 360 is:
2 x 2 x 2 x 3 x 3 x 5 = 360
Given the initial speed and time elapsed by the car, the negative acceleration that brings the car to a stop at the red light is -5.56m/s².
<h3>What is the acceleration of the car?</h3>
Newton's first equation of motions states that;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time.
Given the data in the question;
- Since the car is stopping, final velocity v = 0
- Initial velocity u = 80 km/h
- Time elapsed t = 4s
- Acceleration = ?
First, convert the unit of the initial velocity from kilometer per hour to meter per seconds
Initial velocity = 80 km/h = ( 80 × 5/18 )m/s = 2.2222 m/s
Now, plug these values into the equation above and solve for a.
v = u + at
0 = 22.2222m/s + ( a × 4s )
a × 4s = -22.2222m/s
a = 22.2222m/s ÷ 4
a = -5.56m/s²
Negative sign shows that the car is slowing down.
Given the initial speed and time elapsed by the car, the negative acceleration that brings the car to a stop at the red light is -5.56m/s².
Learn more about Equations of Motion here: brainly.com/question/18486505
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