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RSB [31]
3 years ago
8

The density of a certain material is such that it weighs 6 kilograms per quart of volume. Express this density in grams per lite

r. Round your answer to the nearest whole number.
Mathematics
1 answer:
fredd [130]3 years ago
4 0

Answer:

The density of the material is 6342 grams/liter.

Step-by-step explanation:

Given that,

The density of a certain material is such that it weighs 6 kilograms per quart of volume.  We need to find the density in grams per liter.

We know that,

1 kg = 1000 g and 1 litre = 1.057 quart

So,

d=6\ \dfrac{\text{kg}}{\text{quart}}\\\\=6\times \dfrac{1000\ \text{g}}{\dfrac{1}{1.057}\ \text{liter}}\\\\d=6342\ \text{g/liter}

Hence, the density of the material is 6342 grams/liter.

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20. A ball is dropped from a height of a little over 5 feet, and the height is measured at small intervals. The table below show
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Step 1:

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\begin{gathered} P(t)=-15.64t^2\text{ - 1.24t + 5.2}3 \\ =\text{ -15.64 }\times0.3^2\text{ - 1.24}\times\text{ 0.3 + 5.2}3 \\ =\text{ -1.4076 - 0.372 + }5.23 \\ =\text{ 3.45} \end{gathered}

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\begin{gathered} p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ =\text{ -15.64}\times0.52^2\text{ - 1.23}\times0.52\text{ + 5.23} \\ =\text{ -4.23 - 0.64 + 5.23} \\ =\text{ 0.36} \end{gathered}

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\begin{gathered} p(t)\text{ = 1} \\ p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ 1=-15.64t^2\text{ - 1.23t + 5.23} \\ -15.64t^2\text{ - 1.23t + 4.23 = 0} \\ t\text{ = 0.48222} \\ \text{t = 0.48 seconds} \end{gathered}

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