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3 years ago

URGENT 100 POINTS

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

6 0

Answer:

The missing side length is 5 cm

Step-by-step explanation:

We see that 4cm is on the top and 9 cm is on the bottom.

All we need to do is subtract 4 from 9

9-4=5

The missing side length is 5 cm

polet [3.4K]3 years ago

4 0

Answer:

the missing length is 7cm and the whole perimeter is 52cm

Step-by-step explanation:

to get the missing length take 4 and 11 and subtract it

4-11=7

then add it all together and you get 52cm

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Bus one had half of the grade eight students and 6 grade, seven students, bus two had 15 grade seven students and one-third of g

Rzqust [24]

I'm not sure about that one

7 0

3 years ago

A bicycle tire has a diameter of 62 \text{ cm}62 cm62, start text, space, c, m, end text. What is the distance the bicycle tire

navik [9.2K]

Answer:

The distance bicycle tire travels is 1946.8 cm.

Step-by-step explanation:

Given:

Diameter of bicycle tire = 62 cm.

The bicycle tire travels in 10 revolutions.

Now, to find the distance the bicycle tire travels in 10 revolutions.

Diameter = 62 cm.

Radius (r) = $\frac{Diameter}{2}=\frac{62}{2}=31\ cm.$

So, we get the circumference first by putting formula:

$Circumference =2\pi r$

$Circumference =2\times 3.14\times 31\\\\Circumference =194.68\ cm.$

Thus, we get the circumference of tire 194.68 cm.

Number of revolutions the tire travels = 10.

Now, to get the distance the bicycle tire travels we multiply circumference of tire by number of revolutions the tire travels:

$194.68\ cm\times 10\\\\=1946.8\ cm.$

Therefore, the distance bicycle tire travels is 1946.8 cm.

4 0

3 years ago

Read 2 more answers

The drama club has 120 members. 48

marissa [1.9K]

<h3>Answer: 40%</h3>

Work Shown:

48/120 = 0.40 = 40%

6 0

2 years ago

Read 2 more answers

Choose the domain for which each function is defined

klemol [59]

Answer:

Part 1) $f(x)=\frac{x+4}{x}$ -----> $x\neq 0$

Part 2) $f(x)=\frac{x}{x+4}$ ----> $x\neq -4$

Part 3) $f(x)=x(x+4)$ ----> All real numbers

Part 4) $f(x)=\frac{4}{x^2+8x+16}$ ----> $x\neq -4$

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

$f(x)=\frac{x+4}{x}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=0 the function is not defined

therefore

The domain is

$x\neq 0$

Part 2) we have

$f(x)=\frac{x}{x+4}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

Part 3) we have

$f(x)=x(x+4)$

Applying the distributive property

$f*(x)=x^2+4x$

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

In a quotient the denominator cannot be equal to zero

Equate the denominator to zero

$x^2+8x+16=0$

Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

6 0

3 years ago

A triangle has 2 sides of lengths 6 and 9. what value could the 3rd length be

Tpy6a [65]

Anything greater than 4 but less than 9

5 0

3 years ago