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3 years ago

Could someone please tell me the answer

Mathematics

1 answer:

NARA [144]3 years ago

5 0

Its 10.4 you are correct

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Find the equation of a line in slope-intercept form, containing the points (9,2.6) and (8,2.2).

Zolol [24]

The equation in slope-intercept form would be y = 0.4x - 1

hope this helps!!

4 0

3 years ago

Please help me with this!!!!

Crazy boy [7]

Answer:

The answer is C

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can someone please help me with this

sweet-ann [11.9K]

Answer:

(D) 29.3

Step-by-step explanation:

The answer is all the days added together and then divided by 10.

20+30+40+38+25+22+39+22+26+31=293.

293/10=29.3

3 0

2 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

5 0

3 years ago

Read 2 more answers

The playing life of a Sunshine radio is normally distributed with mean LaTeX: \muμ = 600 hours and standard deviation LaTeX: \si

Hitman42 [59]

Answer:

The probability that a radio selected at random will last from 600 to 700 hours is 0.3413

Step-by-step explanation:

The playing life of a Sunshine radio is normally distributed

Mean = $\mu = 600 hours$

Standard deviation = $\sigma = 100 hours$

We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)

Formula: $Z= \frac{x-\mu}{\sigma}$

At x = 600

$Z= \frac{600-600}{100}$

Z=0

$P(X$

At x = 700

$Z= \frac{700-600}{100}$

Z=1

$P(X$

$P(600$

Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413

8 0

4 years ago