Answer:
It's growing
Explanation:
The growth rate is 50 rabbits per year
Answer:
Stabilizing selection results in a decrease of a population 's genetic variance when natural selection favors an average phenotype and selects against extreme variations. In directional selection, a population's genetic variance shifts toward a new phenotype when exposed to environmental changes.
Explanation:
I don't bite, don't worry
Answer:
Triacylglycerols are acylglycerols with three fatty acid molecules, generally long chain, which can be the same or different; we speak of simple triacylglycerols when there is the same fatty acid in all three glycerol positions, but most are mixed triacylglycerols, with at least two different fatty acids. The properties of triacylglycerols will depend on the type of fatty acids they contain.
Most of the fats and oils of both animal origin (tallow, butter) and vegetable (olive, corn, sunflower, palm, and coconut oils) are formed almost exclusively by triacylglycerols.
Physiologically, triacylglycerols are an important energy reserve. In most eukaryotic cells, triacylglycerols are stored in the cytosol as microscopic fat droplets. In vertebrates there are specialized cells in the storage of fat, adipocytes. In humans, the presence of fatty tissue under the skin, in the abdominal cavity and in the mammary gland stands out.
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
The answer for this one is A
