Two different rectangles have the same area of 48 square feet but different perimeters what are the dimensions of each rectangle
?
1 answer:
Answer:
4*12 and 6*8
Step-by-step explanation:
4*12= 48
4+4+12+12= 32
6*8= 48
6+6+8+8=28
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Step-by-step explanation:
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Answer:
24
Step-by-step explanation:
use Pythagoras theorem
a^2 + b^2 = c^2
18^2+b^2=30^2
b^2 = 30^2 - 18^2
b = √576 =24