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Katyanochek1 [597]
3 years ago
8

Can the law of sines be used to solve the triangle shown? Explain. 40 45° 30

Mathematics
2 answers:
bulgar [2K]3 years ago
8 0

Answer:

63

Step-by-step explanation:

Maksim231197 [3]3 years ago
5 0

Answer:

Step-by-step explanation:

If BD_|_AC

in trg BDA ,sin 45=BD/40=V2/2

BD*2=40V2

BD=40V2/2=20V2  and AD=BD

so CD=30-AD=30-20V2

in trg BCD,  BC^2=BD^2+CD^2

                     BC^2=(20V2)^2+(30-20V2)^2=

                     (20V2)^2+30^2-2*30*20V2+(20V2)^2=

                     400*2+900-1200V2+400*2=

                     800+900-1200V2+800=

                      2700-1200V2

so  BC=V100(27-12V2)=10V(27-12V2

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The dimensions of the rectangle will be 6 inches and 12 inches.

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Let L be the length and W be the width of the rectangle.

Then the area of the rectangle will be

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brainly.com/question/20693059

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