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4 years ago

Graph the inequality. 4x + 6y 10

Mathematics

2 answers:

Vedmedyk [2.9K]4 years ago

7 0

Answer:

First find the points that line goes across on line x and line y and tie them together.

Step-by-step explanation:

First we need to find the points that the line across to x and y lines.

for x line we need to put 0 instead of y:

$4x=10\\x=5/2$

for y line we need to put 0 instead of x:

$6y=10\\y=5/3$

And the line will be goes over (5/2,0) and (0,5/3) points.

Please check the graph at the attachment.

Vikki [24]4 years ago

6 0

Step 1: Add -6y to both sides.4x+6y+−6y=10+−6y4x=−6y+10Step 2: Divide both sides by 4.4x4=−6y+104x=−32y+52Answer:x=−32y+52

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Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair

umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

Maximum value occurs at 325 at the point (0, 325)

Step-by-step explanation:

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0

3 years ago

A gardener already has four and one over 2 ft of fencing in his garage. He wants to fence in a square garden for his flowers. Th

NikAS [45]

<h2>Answer:</h2>

$6\frac{1}{2}$ , "six and one over two ft".

<h2>Step-by-step explanation:</h2>

Let's considerate the fact that the garden has a square shape.

<h3>1. Finding values of interest.</h3>

Amount of fence that the gardener already has: $4\frac{1}{2}$ ft.

Length of one side: $2\frac{3}{4}$ ft.

If one side measures $2\frac{3}{4}$ ft, and the square garden has 4 sides of equal length, because it's a square, then we must multiply the measure of one side by 4 to find the total length of fence needed:

$4*(2\frac{3}{4})=\\ \\4*(2+\frac{3}{4})=\\ \\(4*2)+(4*\frac{3}{4})=\\ \\8+(\frac{12}{4} )=\\ \\8+3=\\ \\11$

The gardener already has $4\frac{1}{2}$ , which equals $4 + \frac{1}{2}$ . Hence, the difference between the amount needed and the amount that the gardeneralready has will give us the remaining amount required. Let's do that:

$11-(4+\frac{1}{2} )=\\ \\11-(\frac{8}{2} +\frac{1}{2} )=\\ \\11-\frac{9}{2}= \\ \\\frac{22}{2} -\frac{9}{2}=\\\\ \frac{13}{2}$

<h3>3. Express your result.</h3>

$\frac{13}{2} =\\ \\\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{1}{2}= \\ \\6+\frac{1}{2}=\\ \\6\frac{1}{2}$

8 0

2 years ago

If the problem says x=5 ,did it give you a input or output?

Thepotemich [5.8K]

It gave you the input because it is telling you what x is

8 0

3 years ago

Read 2 more answers

PLZ HELP WILL GIVE BRAINLIEST!!!!!!!!

Nimfa-mama [501]

C is the best one I'm pretty sure it makes the most sense

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4 years ago

Read 2 more answers

Joel’s veterinarian tells him that he can give his dog 11 5/8 mg of Benadryl for relief of his dogs allergies. Joel’s dog weighs

Sav [38]

Step-by-step explanation:

Given that,

The dosage of Benadryl for Dog is $11\dfrac{5}{8}\ mg$

Weight of Joel's Dog is $15\dfrac{1}{2}\ \text{pounds}$

(a) Benadryl dosage per pound for Joel’s dog is calculated as :

$\dfrac{11\dfrac{5}{8}}{15\dfrac{1}{2}}=\dfrac{\dfrac{11\times 8+5}{8}}{\dfrac{15\times 2+1}{2}}\\\\=\dfrac{\dfrac{93}{8}}{\dfrac{31}{2}}\\\\=\dfrac{93}{8}\times \dfrac{2}{31}\\\\=0.75\ \text{dosage per pound}$

(b) If the weight of the Dog is 12 pounds, it means

$\dfrac{11\dfrac{5}{8}}{12}\ \text{dosage per pounds}\\\\=\dfrac{\dfrac{93}{8}}{12}\\\\=\dfrac{93}{8}\times \dfrac{1}{12}\\\\=0.968\ \text{dosage per pounds}$

Therefore, this is the required solution.

3 0

3 years ago