C and D would be the answer
The answer is B hope it helps
Answer:

Step-by-step explanation:
Arithmetic sequence:

Here a is the first term and d is the common difference.
⇒
------------(I)
⇒ a + 19d = 100 ---------(II)
Subtract equation (I) from (II)
(I1) a + 19d = 100
(II) a + 13d = 46
<u>- - -</u>
6d = 54
d = 54 ÷ 6

Substitute d = 9 in equation(I) and find 'a',
a + 13*9= 46
a + 117 = 46
a = 46 - 117
a = -71

= -71 + 18
= -53

= -71 + 54
= -17

= -71 + 9*n - 1 *9
= -71 + 9n - 9
= -71 - 9 + 9n
= - 80 + 9n
1)
2(a + 3) = -12
Divide by 2
a + 3 = -6
Subtract 3
a = -9
2)
3(p + 2) = 18
Divide by 3
p + 2 = 6
Subtract 2
p = 4
3)
4(2r + 8) = 88
Dive by 4
2r + 8 = 22
Subtract 8
2r = 14
Divide by 2
r = 7
4)
2(3a + 2) = -8
Divide by 2
3a + 2 = -4
Subtract 2
3a = -6
Divide by 3
a = -2
5)
4(k + 3) = 4
Divide by 4
k + 3 = 1
Subtract 3
k = -2