1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mafiozo [28]
3 years ago
5

Need a quick answer please

Mathematics
1 answer:
Ksivusya [100]3 years ago
7 0

Answer:

m<1=41

m<2=85

m<3=95

m<4=85

m<5=36

Step-by-step explanation:

180-144=36

180-95=85

180-85=95

90+49=139

180-139-41

You might be interested in
Which greatest digit should replace n so that the number 342n84 is divisible by 3?
Amiraneli [1.4K]

Answer:

9

Step-by-step explanation:

If you want the number to be divisible by three make sure the sum of all the numbers are divisible by three. Add all the numbers you have to see what they make.

3+4+2+8+4=21

So we just need to find the greatest number we can add to that to have it remain divisible by three. A number divisible by three is 30, and we can add 9 to 21 to make 30. Of course, there are other numbers we could add, but nine is the largest one-digit number that would work. Other smaller numbers include 3 and 6.

3+4+2+8+4+9=30

Now we check to see if our number is divisible by three

342984÷3 = 114328

114328 is a whole number so we know it's divisible.

6 0
3 years ago
***NEED ANSWERS IN NEXT 10 MINUTES*** The local nursery is making a rectangular display area for new shrubs and wants to put up
Alecsey [184]

Answer:

is today your exam or test

Can I Help you

️️

5 0
3 years ago
Calculate the average for this list of numbers: 2000.56    709.90    3.45    67.34    550.90
Neko [114]
Add them all up then divide by 5, so it should be 666.43
4 0
4 years ago
Please help its due today
nlexa [21]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In a survey of 248 people, 156 are married, 70 are self-employed, and 25 percent of those who are married are self-employed. If
MatroZZZ [7]

Answer:

The probability of selecting a  person which is  self-employed but not married equals 1/8.

Step-by-step explanation:

Here, the given survey says:

Total number of people surveyed = 248

Number of people married = 156

The number of people are self employed = 70

Now, 25% of people who are married are SELF EMPLOYED.

Now, calculating 25% of 156 , we get:

\frac{25}{100} \times 156 = 39

⇒ out of total 156 married people, 39 are self employed.

So, number of  self employed people but  not married

= Self employed people - Self employed people PLUS  married

=  70  -  39   =  31.

So, the probability that the person selected will be self-employed but not married = \frac{\textrm{The total number of people self-employed but not married}}{\textrm{Total Number of people}} =  \frac{31}{248}  = \frac{1}{8}

Hence The probability of selecting a  person which is  self-employed but not married equals 1/8.

7 0
3 years ago
Other questions:
  • if it takes 30 steps to walk from the front of the store to the back and 40 steps to walk from the left of the store to the righ
    10·2 answers
  • Find the vertices and foci of the hyperbola with equation quantity x plus 4 squared divided by 9 minus the quantity of y minus 5
    6·1 answer
  • Which of the following expressions demonstrates the distributive property?
    6·1 answer
  • Ray’s favorite gun comes in tape form. He had 5 feet of gum and cut 4 pieces that were each 5/6 foot long. How much fun did he h
    7·1 answer
  • Answer for this question
    14·1 answer
  • What percent of teenage boys masturbate before reaching 18
    7·2 answers
  • 1. When given the expression 5^3, what should you do to solve?
    14·1 answer
  • Which expression is equivalent to y x 36?
    15·1 answer
  • Neil and his mom are volunteering at an emergency relief center. To help prepare in case of a flood, they pack emergency kits wi
    5·1 answer
  • Write the equation of the line in either point-slope form or slope-intercept form.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!