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Svetradugi [14.3K]
3 years ago
6

In a survey of 248 people, 156 are married, 70 are self-employed, and 25 percent of those who are married are self-employed. If

a person is to be randomly selected from those surveyed, what is the probability that the person selected will be self-employed but not married?
Mathematics
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

The probability of selecting a  person which is  self-employed but not married equals 1/8.

Step-by-step explanation:

Here, the given survey says:

Total number of people surveyed = 248

Number of people married = 156

The number of people are self employed = 70

Now, 25% of people who are married are SELF EMPLOYED.

Now, calculating 25% of 156 , we get:

\frac{25}{100} \times 156 = 39

⇒ out of total 156 married people, 39 are self employed.

So, number of  self employed people but  not married

= Self employed people - Self employed people PLUS  married

=  70  -  39   =  31.

So, the probability that the person selected will be self-employed but not married = \frac{\textrm{The total number of people self-employed but not married}}{\textrm{Total Number of people}} =  \frac{31}{248}  = \frac{1}{8}

Hence The probability of selecting a  person which is  self-employed but not married equals 1/8.

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A similar problem is given at brainly.com/question/14510808

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