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spayn [35]
3 years ago
9

Could JKL be congruent to XYZ? Explain.

Mathematics
2 answers:
Aloiza [94]3 years ago
4 0

Answer:

The could be congruent since the have an equal side length and when XYZ gets rotated it can get mapped on to JKL

Step-by-step explanation:

hope this helpsss

jenyasd209 [6]3 years ago
3 0

Answer:yes

Step-by-step explanation:

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Please help with answer and number line​
goblinko [34]

Answer:

Graph uploaded!

Step-by-step explanation:

<u>First, let's solve the distributive property.</u>

  • 4/5(x - 2) ≤ 6
  • => 4x/5 - 8/5 ≤ 6
  • => 4x/5 ≤ 6 + 8/5
  • => 4x/5 ≤ 38/5
  • => x ≤ 19/2

Now, let's plot this inequality on the line. Please check my graph.

Hoped this helped!

6 0
2 years ago
CAN SOMEONE PLEASE HELP ME???
zmey [24]

Step-by-step explanation:

the graph A is represents the ordered pairs.

4 0
3 years ago
the cost of a family membership at the health club is $58 per hour plus a one-time $129 start up fee. If a family paid $651, the
sweet [91]
The equation would be 651=58x+129. Subtract 129 from both sides of the equation. you get 522=58x. Then divide both sides of the equation by 58 to get x alone and you get 9=x. The membership is 9 months. Hope I helped and if you have any questions, just leave a comment.
8 0
3 years ago
Y=2x-3<br>x+y=12<br><br><br><br><br><br><br><br>help me pls
Andreas93 [3]

Answer:

(5,7)

Step-by-step explanation:

Substitute 2x-3 for y in the 2nd equation, obtaining:  x + 2x - 3 = 12.  Then 3x = 15, and x = 5.  Subbing 5 for x in the 1st equation results in:  y = 2(5) - 3 = 7.  The solution is therefore (5,7).


7 0
3 years ago
The two-way table shows the distribution of gender to favorite film genre for the senior class at Mt. Rose High School.
Studentka2010 [4]

Answer:

The second statement is correct

Step-by-step explanation:

Hello!

The table shows the information of the favorite film genre of the students of the class regarding their gender.

You have to prove which statement is correct:

1)The probability of randomly selecting a student who has a favorite genre of drama and is also female is about 17 percent.

If you chose a student at random, you need to calculate the probability of its favorite genre being "Drama" (D) and the student being female (F), symbolically: P(D∩F)

To do so you have to divide the number of observed students that are female and like drama by the total number of students:

P(D∩F)= \frac{24}{240}= \frac{1}{10} =0.10

This means that the probability of choosing a student at random and it being a female that likes drama is 10%.

<em>This statement is incorrect.</em>

2) Event F for female and event D for drama are independent events.

Two events are independent when the occurrence of one of them doesn't affect the probability of occurrence of the other one.

So if F and D are independent then:

P(F)= P(F|D)

-or-

P(D)=P(D|F)

The probability of the event "Female" is equal to P(F)= \frac{Total females in the class}{n} = \frac{144}{240} = \frac{3}{5}= 0.6

The probability of the event "Drama" is:

P(D)= \frac{Total students that like "Drama"}{n}= \frac{40}{240}= \frac{1}{6}= 0.166

P(F|D)= \frac{P(FnD)}{P(D)}= \frac{\frac{1}{10} }{\frac{1}{6} }= \frac{3}{5}  = 0.6

As you can see P(F)= 0.6 and P(F|D)= 0.6 so both events are independent.

<em>This statement is correct.</em>

3) The probability of randomly selecting a male student, given that his favorite genre is horror, is  16/40

This is a conditional probability, you already know that the student likes horror movies (H), and out of that group you want to know the probability of the student being male (M):

P(M|H)= \frac{number of male students that like horror movies}{total students that like horror movies}= \frac{16}{38}= \frac{8}{19}   = 0.42

<em>This statement is incorrect.</em>

4) Event M for male and event A for action are independent events.

Same as the second statement, if the events "Male" and "Action" are independent then:

P(M)= P(M|A)

-or-

P(A)= P(A|M)

P(M)= \frac{96}{240}= \frac{2}{5}= 0.4

P(A)= \frac{72}{240} =\frac{3}{10}= 0.3

P(AnM)= \frac{28}{240}= \frac{7}{60}= 0.11666

P(M|A)= \frac{P(MnA)}{P(A)}= \frac{\frac{7}{60} }{\frac{3}{10} }  = \frac{7}{18}= 0.3888

P(M)= \frac{2}{5} and P(M|A)= \frac{7}{18}

P(M)≠ P(M|A) the events are not independent.

<em>This statement is incorrect.</em>

<em />

I hope this helps!

6 0
3 years ago
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