Please help solve this (8x-4)(x^{3}-x-5)

2 answers:

6 0

Equation.
(x−1)(x−2)2=0(x-1)(x-2)2=0
If any individual factor on the left side of the equation is equal to
00
, the entire expression will be equal to
00.x−1=0x-1=0(x−2)2=0(x-2)2=0
Set the first factor equal to
00
and solve.
x=1x=1
Set the next factor equal to
00
and solve.
x=2x=2
The final solution is all the values that make
(x−1)(x−2)2=0(x-1)(x-2)2=0
true.
x=1,2x=1,2

sweet-ann [11.9K]3 years ago

5 0

The answer is 10x - 9

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Read 2 more answers

You roll a 6-sided die.

Lerok [7]

Answer:

$\huge\boxed{\text{P(not factor of 35) = } \frac{2}{3}}$

Step-by-step explanation:

We can use basic probability to find the probability that this roll is not a factor of 35.

First off, we know that with a six sided die there are 6 possible things we can roll.

1, 2, 3, 4, 5, or 6

Now, what are the factors of 35? The factors of 35 will be any whole number that can be multiplied by another whole number to get 35.

We know $1 \cdot 35 = 35$ , so two factors are 1 and 35.
We know $5 \cdot 7 = 35$ , so two factors are 5 and 7.

Therefore, the factors of 35 are 1, 5, 7, 35.

Both 5 and 7 are inside the range of 1-6. So the probability of rolling a side that's a factor of 35 will be $\frac{2}{6} = \frac{1}{3}$ since there are two factors and 6 possible options.