The equation is:
y = 10 sin(π/15 t) + 30
where 30 represents the initial height of the blade above the ground and π/15 represents the period as we are given that the blade completes two rotation every minute.Finally the 10 represents the length of the blades.
Hope this helps :)
True because if you did 180°-270° it would be in quadrant 3 or it could be on quadrant 2 because quadrant 2 is 90-180
Answer:
A.Y=3/2x-12
Step-by-step explanation:
Option A would be the correct answer.
From this detail that is a right isosceles triangle result that the angles from the base has measure of 45 degrees
- there is given again that the length of legs is 6"
- than we drawn the height from the right angle on hypotenuse and use sin45 we get
but we need to know that 6" = 6*2,6 = 15,6 cm = 0,156 m
cos 45° = (half of hypotenuse)/6"
sqrt2 /2 = (half of hyp) /6"
half of hyp. = 6"sqrt2 /2 = 3sqrt2" so than the length of hypotenuse will be
equal 2*3sqrt2 = (6sqrt2)"
<span>Let t
= travel time at 58</span>
<span>and
(6-t) = travel time at 49
distance at 58 + distance at 49 = 325.5 mi</span>
<span>
58t + 49(6-t) = 325.5
58t + 294 - 49t = 325.5</span>
9t+294
= 325.5
9t
=31.5
T =
31.5/9 = 3.5 hours at 58 mph
6-3.5
= 2.5 hours at 49 mph
<span> Check:</span>
58*3.5
= 203
49*2.5=
122.5
203+122.5
= 325.5
