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Gennadij [26K]
3 years ago
8

Find the missing values 3:4=6:__=9:_=12:_=15:_

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

Step-by-step explanation:

6:8=9:12=12:16=15:20

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1224 / 12 = 102

He will be paying $102 a month for his TV

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What is the 0.9 to the power of 2
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Answer:

.81

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The temperature is 45F. The temperature will decrease by 2F each hour.
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2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
3 years ago
Read 2 more answers
Help quick please!!
Korolek [52]

Answer:

Difference of squares:

y^4−25

16x^2−81

Not difference of squares:

20m^2n^2−121

p^8−q^5

Step-by-step explanation:

y^4−25

(y²)² - 5²

16x^2−81

(4x)² - 9²

20m^2n^2−121

20 is not a perfect square

p^8−q^5

q⁵ is not a perfect square

3 0
3 years ago
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