I have no idea, but the only thing that comes to mind, is the fact, 80+20=100 and you need to find the value of 70 which can be taken out of the 100 .. but simply the 20% has a variable. Find a way to use that.
Answer:
Expresion:
![\frac{2}{5}(\frac{5}{6}*42)](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%7D%7B6%7D%2A42%29)
Evaluating:
![\frac{2}{5}(\frac{5*42}{6})=\frac{2}{5}(\frac{210}{6})=\frac{2*210}{5*6}=\frac{420}{30}=14](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%2A42%7D%7B6%7D%29%3D%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B210%7D%7B6%7D%29%3D%5Cfrac%7B2%2A210%7D%7B5%2A6%7D%3D%5Cfrac%7B420%7D%7B30%7D%3D14)
Step-by-step explanation:
By definition, a product is the result of a multiplication. For example:
![a*b=c](https://tex.z-dn.net/?f=a%2Ab%3Dc)
In this example "a" and "b" are the factors and "c" is the product.
Therefore, given:
"
of the product
and
"
You can observe that it indicates that the result obtained by multiplying
and
, is multiplied by
.
Knowing this, you can write the following expression:
![\frac{2}{5}(\frac{5}{6}*42)](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%7D%7B6%7D%2A42%29)
Finally, evaluating, you get this result:
![\frac{2}{5}(\frac{5*42}{6})=\frac{2}{5}(\frac{210}{6})=\frac{2*210}{5*6}=\frac{420}{30}=14](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%2A42%7D%7B6%7D%29%3D%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B210%7D%7B6%7D%29%3D%5Cfrac%7B2%2A210%7D%7B5%2A6%7D%3D%5Cfrac%7B420%7D%7B30%7D%3D14)
1X0.28
dude thats easy man
Answer:
8550
Step-by-step explanation: