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lara [203]
3 years ago
9

An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba

sis of body mass index (BMI), expressed as weight/height2. An adult is considered overweight if the BMI is 25 or more but less than 30. An obese adult will have a BMI of 30 or greater. According to a January 2012 article in the Journal of the American Medical Association, 33.1% of the adult population in the United States is overweight and 35.7% is obese. Use this information to answer the following questions.
a.
What is the probability that a randomly selected adult is either overweight or obese? (Round your answer to 3 decimal places.)



Probability


b.
What is the probability that a randomly selected adult is neither overweight nor obese? (Round your answer to 3 decimal places.)



Probability
Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

(a) The probability that a randomly selected adult is either overweight or obese is 0.569.

(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.

Step-by-step explanation:

Let <em>A</em> = a person is over weight and <em>B</em> = a person is obese.

The information provided is:

An adult is considered overweight if the BMI ≥ 25 but BMI < 30.

An obese adult will have a BMI ≥ 30.

According to the range of BMI the events A and B are independent.

P (A) = 0.331 and P (B) = 0.357.

(a)

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B)

               = P (A) + P (B) - P (A)×P (B)

               =0.331+0.357-(0.331\times0.357)\\=0.569833\\=0.569

Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.

(b)

Compute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(A^{c}\cup B^{c})=1-P(A\cup B)=1-0.569=0.431

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.

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