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3 years ago

Please hurry

Mathematics

1 answer:

maksim [4K]3 years ago

7 0

Answer:

it should be : x²= 15²+8²

x²= 225+64

x²=289

x=√289

x=17

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Which of the following statements is true

kolbaska11 [484]

Answer:

D. This quadratic equation two complex solutions.

Step-by-step explanation:

$5x^2 +6x +2= 0\\$

Equating it with

$ax^2 +bx +c= 0\\$

a = 5, b = 6, c = 2

$b^2 -4ac\\= 6^2 - 4\times 5\times 2\\= 36-40\\b^2 -4ac= - 4\\$

$\because b^2 -4ac$ is negative.

Therefore, this quadratic equation two complex solutions.

5 0

3 years ago

In a group of 36 children, there are twice as many boys as girls, how many girls are there?

larisa86 [58]

12
For every 1girl there are 2boys

1girl+2boys= 3/1girl

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4 years ago

-6y+15= -27 what is y?

stealth61 [152]

Answer:

y=7

Step-by-step explanation:

-6y= -27-15

-6y= -42

y=7

8 0

3 years ago

Read 2 more answers

Subtract rational expression. <br> Show work please.

yan [13]

Given:

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}$

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor $x^2-1$ . It can be written as $x^2-1^2$ .

$x^2-1^2=(x-1)(x+1)$ using algebraic identity.

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}$

LCM of $x-1,(x+1)(x-1)=(x+1)(x-1)$

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

$$=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}$

Now, denominators are same, you can subtract the fractions.

$$=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}$

Expand $(x+4)(x+1)-5$ .

$$=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}$

$$=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

6 0

3 years ago

Drey makes $10 an hour plus $15 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week

blsea [12.9K]

490=10·40+15x

490=400+15x

90=15x

x=6

he worked a total of 46 hours

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4 years ago